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components 12 and -20 the tangent of the angle is y/x
is(W) supposed to be length or magnitude?
I'd be more specific and state that the horiz. comp. is 12 and that the vert. comp. is -20. I'd also suggest that you sketch this situation, and then determine which trig function is best suited to help you find the angle. You're looking for the MAGNITUDE of W.
\[\left| \left| W \right| \right|\]
In this particular case, the length is pretty much the same as the magnitude.
magnitude Im sure. that is why i need help with this problem, this is all the information i was given.
i always assume people just need the general direction to go , and get most of it and just cant get started or something.. too wordy lately
You need to determine 2 things: 1) the magnitude of the vector W, and the angle that W makes with the x-axis.
i think that is what i need help with, just getting started. Ive gone through the lesson numerous of times and examples but there is just so little information given
and all i have to do is find the angle between where the x axis and vector w? Im sorry, math is not my forte
ok, notice the components are parallel to the axis the sides make right angles with x and y axis, you have right triangles
yes, i see
and i have to find out the two missing angles?
there is the angle, you can use the tangent function to relate opposite side / adjacent side, or y dist / x dist tan(a) = y / x
one of them will be negative tangent(a) = sin(a) / cos(a), in quadrant 4, sin(a) is negative, and cos(a) is pos a = tan^(-1)(-20 / 12) or about -59 degrees
starting at the +x-axis being 0 degrees... counter clockwise is the + direction
the magnitude of the vector is the length from head to tail... it is the hypotenuse of a right triangle with those components, use the pythagorean theorem W magnitude = sqrt( 20^2 + 12^2)
i have no idea honestly