At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
what do you get for Z and mu?
Sorry. 3.98 would be the sample mean. For Z I would assume we'd be using the normal confidence interval for 95% of 1.96
im getting 3.483 as a mean ... but most of that was adding in my head
The distribution is poisson though right? So the confidence interval is going to be asymmetric.
Cause if you take the answers they've given it's not centered around either of our answers for the mean
4.015 yeah ... i spose we would work it so that we have a left tail of 5/2 and a right tail of 5/2
i spose we have a calculator for this? or tables?
Yeah, I have an appendix of tables and calculator access is fine. Is there a specific table you wanted me to check?
i dont have much experience in poisson, but im sure the table is one with ns and percentages .. similar to a t-distribution table
Poisson is asymmetric, this is what it'd look like for 3.98 : http://puu.sh/lLXfR/bcf3692e4b.png So it'd make sense that it'd be centered around 2.015 for a confidence interval
how do we determine say the value of X, such that 2.5% is in a left tail?
I'm not sure. That's where I'm having trouble
http://onbiostatistics.blogspot.com/2014/03/computing-confidence-interval-for.html this would suggest that we simply do a conventional interval method, using the standard error or whatever its called to be sqrt(u/n)
Okay. I've been using the normal approximation thus far, and that's giving me the wrong values. I'll see if I can follow their method for the exact values
So according to this table (our provided table doesn't go up to n=50) the value we should be using is 32.357 I think? Am I reading this correctly?
Wait nevermind I'm dumb
So we need to enter in the custom value of 3.98 for the formula for chi squared?
http://puu.sh/lLY9r/271ebc29d4.png Trying this thing.
im getting a mean of 3.98 3.98 - 1.96sqrt(3.98/60) = 3.475 3.98 + 1.96sqrt(3.98/60) = 4.485 which of course is not what the solutions say it is .... so they must have gone a different route eh. and i cant really make sense of that last link you posted.
On the link you posted, it says there are two ways to do it. The normal approximation and the "EXACT method"
The exact method relies on chi squared: (qchisq(α/2, 2*x)/2, qchisq(1-α/2, 2*(x+1))/2 )
And that link I posted in the chi squared formula I think? I may be looking at the wrong thing.
Whatever the answer is, its definitely not going to be of the form 3.98+- something right? Otherwise the interval would be centered around 3.98
correct, that method is approximation, im reading up in a chi^2 method
but your hint suggests the approximation method if im reading it right
Right. I think the hint is just misleading.
Unless there's some easy way to derive mu from x bar.
I don't know enough about poisson though, and google searches didn't find anything
So this website's calculator got fairly close: http://calculator.tutorvista.com/confidence-interval-calculator.html http://puu.sh/lLZsZ/6ee99f02c1.png Close enough that it may be me entering something in wrong
without having gone thru your materials, id have to say that i am just too inexperienced to determine a suitable solution process at the moment.
Would it help if I provided the associated chapter? I believe its on google books
it would be useful, but i cant guarentee anything from it
Actually having some trouble finding it, sorry. Alright, thank you for your help either way. Helping me think through the problem has been help enough. Thank you.
the best of luck to you :)