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You want to find \(n, (n+1), (n+2)\) such that \(3(n+(n+2)) = 24+ 4(n+1)\). Can you solve this for n?
no... lol I'm not that good at math
try multiplying a bit
and adding like terms
for example n+(n+2) is the same as n+n+2 which is the same as?
2n + 2?
yes not do the multiplying part there is lots of places where you can use distributive property that is if you have a(b+c) then this is equal to a*b+a*c
now what? lol
so you have done the distributing part? and you are asking for what step next? if so please show what you have...
6n + 6 = 24 + 4n + 4
great now collect like terms because you have some on the right hand side
6n + 6 = 28 + 4n
right now get your n terms on one side and your terms without n on the opposing side
do this by adding/subtracting terms on both sides
2n = 22 ?
6n-4n=28-6 2n=22 is right
n = 11 right?
and oops I just realized the problem said even
the word even is very important here
Oops, my bad.
\[3(n+[n+4])=24+4(n+2)\] solve for n all over again lol
its fine those tiny words get looked over sometimes I should have checked
would it be 6n + 4 = 24 + 4n + 8?
no 3(2n+4)=6n+12 not 6n+4
6n + 12 = 24 + 4n + 8
6n + 12 = 32 + 4n
great too :)
you are almost there
2n = 20
n = 10?
right n=10 n+2=10+2=12 n+4=10+4=14 so the three numbers in question are 10,12,14
Thank you so much!
I don't think @AlixxKK would benefit from a Mathematica script; it isn't really suitable for this level.