At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
A solid cylinder (radius = 0.180 m, height = 0.170 m) has a mass of 16.9 kg. This cylinder is floating in water. Then oil (ρ = 702 kg/m3) is poured on top of the water until the situation shown in the drawing results. How much of the height of the cylinder is in the oil?
@IrishBoy123 Any chance you can help with this one :) !
sure but you need to show the drawing..... :p
the solution will require the knowledge that the mass of all fluid(s) displaced by the floating body will equal the mass of the cylinder, ie 16.9kg, ie Archimedes Law: "a floating body displaces it's own mass of the fluid in which it floats"
Thank a lot! For some reason I got the wrong answer though. I used your wolfram formula as a guide - and this is what I got with my numbers. but it was incorrect
this any better?!?! http://www.wolframalpha.com/input/?i=%2816.9+-+1000*pi*0.18%5E2%280.17%29%29%2F%28pi*0.18%5E2+*+%28720-1000%29%29
That number seems rather small.. only 1.417% It may be correct! I am unsure. I am wary of entering it into my assignment, as it is my last attempt for credit
@mathstudent55 @dan815 Can you guys take a look at this thread?
according to archimedes principle bouyant force = weight of fluid displaced
oil will exert a downward force and water will exert an upward force, so we need to balance forces, weight of displaced oil + weight of cylinder = weight of water displaced
\(\rho_1\): density of oil \(\rho_2\): density of water \[\rho_1 \pi r^2 h_1g+mg=\rho_2 \pi r^2 h_2 g\]
and h1+h2= 0.17