askme12345
  • askme12345
Please help!! (Stumped!)
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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askme12345
  • askme12345
A solid cylinder (radius = 0.180 m, height = 0.170 m) has a mass of 16.9 kg. This cylinder is floating in water. Then oil (ρ = 702 kg/m3) is poured on top of the water until the situation shown in the drawing results. How much of the height of the cylinder is in the oil?
askme12345
  • askme12345
@IrishBoy123 Any chance you can help with this one :) !
IrishBoy123
  • IrishBoy123
sure but you need to show the drawing..... :p

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IrishBoy123
  • IrishBoy123
the solution will require the knowledge that the mass of all fluid(s) displaced by the floating body will equal the mass of the cylinder, ie 16.9kg, ie Archimedes Law: "a floating body displaces it's own mass of the fluid in which it floats"
askme12345
  • askme12345
Here's the diagram :)
IrishBoy123
  • IrishBoy123
|dw:1449445094589:dw|
askme12345
  • askme12345
Thank a lot! For some reason I got the wrong answer though. I used your wolfram formula as a guide - and this is what I got with my numbers. but it was incorrect
IrishBoy123
  • IrishBoy123
this any better?!?! http://www.wolframalpha.com/input/?i=%2816.9+-+1000*pi*0.18%5E2%280.17%29%29%2F%28pi*0.18%5E2+*+%28720-1000%29%29
askme12345
  • askme12345
That number seems rather small.. only 1.417% It may be correct! I am unsure. I am wary of entering it into my assignment, as it is my last attempt for credit
askme12345
  • askme12345
@mathstudent55 @dan815 Can you guys take a look at this thread?
baru
  • baru
according to archimedes principle bouyant force = weight of fluid displaced
baru
  • baru
|dw:1449464143541:dw|
baru
  • baru
oil will exert a downward force and water will exert an upward force, so we need to balance forces, weight of displaced oil + weight of cylinder = weight of water displaced
baru
  • baru
|dw:1449464323503:dw|
baru
  • baru
\(\rho_1\): density of oil \(\rho_2\): density of water \[\rho_1 \pi r^2 h_1g+mg=\rho_2 \pi r^2 h_2 g\]
baru
  • baru
and h1+h2= 0.17

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