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How about using math symbols for math? It'll make it much easier to read.
You can write it like this x^3 - 2x^2 - 24x, or even better like this \(x^3 - 2x^2 - 24x\)
How do I do that???
Did I understand the expression correctly?
The first one is simply typing on your keyboard. The second uses the Equation Editor (blue box below), or writing in Latex.
Ok. Let's get to your problem.
The first step in factoring an expression is to look for a common factor. Look at each term. Look at both the coefficients (the numbers) and the variables. Is there a common factor that can be factored out?
|dw:1449448804446:dw| That is what I go t I am not sure how to simplify after that
Good. That is what I meant. You pulled out a common factor of x. That is a good start.
What should I do next?
Is the common factor 2 b/c 2 divided by 24 is 12??
|dw:1449449014597:dw| The blank spot are the spots I am not sure about
Now you have a trinomial to factor. Your trinomial is \(x^2 - 2x - 24\) As you can see, the coefficient of the \(x^2\) term is 1. That is called the leading coefficient. To factor a square trinomial with a leading coefficient of 1 1, all you need to do is come up with 2 numbers that multiply to the last coefficient and add to the middle coefficient. You need 2 numbers that multiply to -24 and add to -2.
Only -2 goes into and -24
How can 12*2 (=24) Add to Two????
|dw:1449449240815:dw| Is that correct?
-24 = -1 * 24 -24 = -24 * 1 -24 = -2 * 12 -24 = -12 * 2 -24 = -3 * 8 -24 = -8 * 3 -24 = -4 * 6 -24 = -6 * 4 As you can see, there are 8 different pairs of numbers that multiply to -24. How many of those pairs of numbers add to -2?
What you did above in incorrect for two reasons. The numbers -2 and -12 multiply to POSITIVE 24, not -24. Also, -2 and -12 do not add to -2.
Correct. The numbers are -6 and 4.
Thanks SO SOSOOSOSOSO MUCH!!!!
You're welcome. Remember what you learned here. 1. To factor an expression always start by trying to factor a common factor out of all terms. 2. To factor a square trinomial with a leading coefficient of 1, all you need is to find two numbers that multiply to the third coefficient and add to the middle coefficient. 3. Then the factorization is (x - one number) (x - the other number)
Thanks I will remember that as I finish my math set!