How many liters of chlorine gas can react with 56.0 grams of calcium metal at standard temperature and pressure? Show all of the work used to find your answer.
Ca + Cl2 yields CaCl2
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For this question, to get the mass of chlorine gas out of the mass of calcium metal, your first course of action should always be converting it into moles, as 1 mol of any substance will create 1 mol of another, therefore the amount of moles of each element in the equation will be the same (keeping in account the stoichiometry of the elements, or the number in front of the element). There is 1 of every element in this equation, so we wont have to worry about that.
Work out the moles of calcium using n = m/M (moles = mass/molar mass)
You can then say that the moles of calcium will be the same as the moles of chlorine gas because one mol of gas creates another so they will have the same molarity.
Then times the amount of moles of chlorine gas by the gas constant (in L) which is 22.4L at STP.
Then you will have your answer! I hope this helps :)