4. A swimmer is swimming across a river that is exactly one mile wide, and the river current is 1.5 mph directly south. If the swimmer can swim through still water at 2.5 mph, and he swims east, perpendicular to the north-south bank, how far downstream will he be carried by the current as he swims across?
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Okay, now label what you know.
thats all i know i can label
There is one more thing you can label. Read the problem statement carefully.
is tht it?
There we go. |dw:1449455729356:dw|
i dont understand how i would do the math on that
Look into pythagorean theorem, and combine that with what tkhunny got you too.
The Net swimming movement is the Net Sum of 2 vectors|dw:1449457648572:dw|
do i find the angle a?
don't really have to for this one
as tkhuny shows, that is what i first thought to, just figure the contributions of both velocity components
even with the current, his horizontal swimming velocity is not changed
he needs to go 1 mile, swimming at that 2.5 mi/h
distance = rate * time
1 mi = 2.5 mi/h * t
It takes 1/2.5 hr to reach the other side
THe whole time the current is pushing him south perpendicular to his swimming direction
In that time 1/2.5 hr, the current will push him down river a distance= 1.5mi/h * 1/2.5 h
omg thank you, you explained it perfectly and helped me with another question i had. you're the first person to help me understand it
notice the velocities are the same ratio as the distances, since it is linear function
could just say
1 mi / (distance down) is the same as 2.5 mi/h / 1.5 mi/h
could have just solved that and been done , but