anonymous
  • anonymous
4. A swimmer is swimming across a river that is exactly one mile wide, and the river current is 1.5 mph directly south. If the swimmer can swim through still water at 2.5 mph, and he swims east, perpendicular to the north-south bank, how far downstream will he be carried by the current as he swims across?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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tkhunny
  • tkhunny
Picture, picture, draw a picture. Do it!
anonymous
  • anonymous
|dw:1449454570134:dw|
anonymous
  • anonymous
so how far will the current take him?

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More answers

tkhunny
  • tkhunny
Okay, now label what you know.
anonymous
  • anonymous
|dw:1449455329249:dw|
anonymous
  • anonymous
thats all i know i can label
tkhunny
  • tkhunny
|dw:1449455508714:dw|
tkhunny
  • tkhunny
There is one more thing you can label. Read the problem statement carefully.
anonymous
  • anonymous
|dw:1449455706135:dw|
anonymous
  • anonymous
is tht it?
tkhunny
  • tkhunny
There we go. |dw:1449455729356:dw|
anonymous
  • anonymous
i dont understand how i would do the math on that
anonymous
  • anonymous
@tkhunny
anonymous
  • anonymous
@mathmale
anonymous
  • anonymous
Look into pythagorean theorem, and combine that with what tkhunny got you too.
DanJS
  • DanJS
The Net swimming movement is the Net Sum of 2 vectors|dw:1449457648572:dw|
DanJS
  • DanJS
|dw:1449457839586:dw|
anonymous
  • anonymous
do i find the angle a?
DanJS
  • DanJS
don't really have to for this one as tkhuny shows, that is what i first thought to, just figure the contributions of both velocity components even with the current, his horizontal swimming velocity is not changed
DanJS
  • DanJS
he needs to go 1 mile, swimming at that 2.5 mi/h distance = rate * time 1 mi = 2.5 mi/h * t It takes 1/2.5 hr to reach the other side
DanJS
  • DanJS
THe whole time the current is pushing him south perpendicular to his swimming direction In that time 1/2.5 hr, the current will push him down river a distance= 1.5mi/h * 1/2.5 h
anonymous
  • anonymous
omg thank you, you explained it perfectly and helped me with another question i had. you're the first person to help me understand it
DanJS
  • DanJS
|dw:1449458625508:dw|
DanJS
  • DanJS
notice the velocities are the same ratio as the distances, since it is linear function
DanJS
  • DanJS
could just say 1 mi / (distance down) is the same as 2.5 mi/h / 1.5 mi/h could have just solved that and been done , but

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