iwanttogotostanford
  • iwanttogotostanford
PLZ H
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
iwanttogotostanford
  • iwanttogotostanford
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
this is the function? \[\Large f(x) = \frac{-x^2-2x-2}{x-2}\]
iwanttogotostanford
  • iwanttogotostanford
yes! @jim_thompson5910

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
ok so you'll type in `(-x^2-2x-2)/(x-2)` into something like https://www.desmos.com/calculator
jim_thompson5910
  • jim_thompson5910
make sure you zoom out so you can see the whole graph
iwanttogotostanford
  • iwanttogotostanford
so when i type that in that is indefinitely my graph visually? @jim_thompson5910
jim_thompson5910
  • jim_thompson5910
there are 2 (disconnected) branches
jim_thompson5910
  • jim_thompson5910
yeah that's what the graph looks like
iwanttogotostanford
  • iwanttogotostanford
two of my answers from my choices look similar but aren't the same
iwanttogotostanford
  • iwanttogotostanford
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
how are they different?
iwanttogotostanford
  • iwanttogotostanford
@jim_thompson5910 they are a tad different
jim_thompson5910
  • jim_thompson5910
can you show me?
iwanttogotostanford
  • iwanttogotostanford
yea @jim_thompson5910
jim_thompson5910
  • jim_thompson5910
ok post a screenshot please
iwanttogotostanford
  • iwanttogotostanford
sorry I'm getting it
jim_thompson5910
  • jim_thompson5910
that's ok, take all the time you need
iwanttogotostanford
  • iwanttogotostanford
1 Attachment
iwanttogotostanford
  • iwanttogotostanford
here is the one that i think is correct
iwanttogotostanford
  • iwanttogotostanford
would you say the same?
anonymous
  • anonymous
When i use the equation i dont get that
iwanttogotostanford
  • iwanttogotostanford
what do u get?
iwanttogotostanford
  • iwanttogotostanford
@hippo211
iwanttogotostanford
  • iwanttogotostanford
could you draw the graph
jim_thompson5910
  • jim_thompson5910
@iwanttogotostanford what does the other graph look like?
iwanttogotostanford
  • iwanttogotostanford
ok, ill give the answer choices and graphs
anonymous
  • anonymous
ok
iwanttogotostanford
  • iwanttogotostanford
A.
1 Attachment
iwanttogotostanford
  • iwanttogotostanford
B.
1 Attachment
iwanttogotostanford
  • iwanttogotostanford
C.
1 Attachment
iwanttogotostanford
  • iwanttogotostanford
D.
1 Attachment
jim_thompson5910
  • jim_thompson5910
if you plugged in x = 0, what would the value of f(0) be equal to?
iwanttogotostanford
  • iwanttogotostanford
which of the graph choices would you say it is?
jim_thompson5910
  • jim_thompson5910
\[\Large f(x) = \frac{-x^2-2x-2}{x-2}\] \[\Large f(0) = \frac{-(0)^2-2(0)-2}{0-2}\] \[\Large f(0) = \underline{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }\] fill in the blank
iwanttogotostanford
  • iwanttogotostanford
i got -2/-2 but i think i did my algebra wrong
jim_thompson5910
  • jim_thompson5910
-2/-2 will reduce to 1
jim_thompson5910
  • jim_thompson5910
so f(0) = 1 this means that the point (0,1) is a point on the graph of f(x)
iwanttogotostanford
  • iwanttogotostanford
yes, true
jim_thompson5910
  • jim_thompson5910
so use desmos to graph and use the fact that (0,1) is on the graph
iwanttogotostanford
  • iwanttogotostanford
so B would be the closest answer, correct?
jim_thompson5910
  • jim_thompson5910
did you use desmos to graph?
iwanttogotostanford
  • iwanttogotostanford
yess
jim_thompson5910
  • jim_thompson5910
https://www.desmos.com/calculator/l7wpprkfxw
iwanttogotostanford
  • iwanttogotostanford
now i am thinking C or D?
anonymous
  • anonymous
thats in wrong the way you enter the info
anonymous
  • anonymous
https://www.desmos.com/calculator/amezlkdjfr look at this
iwanttogotostanford
  • iwanttogotostanford
I'm very confused about which one it would be people
iwanttogotostanford
  • iwanttogotostanford
A, B, C or D??you both are saying different answers
jim_thompson5910
  • jim_thompson5910
@hippo211 I think the first negative only applies to the x^2 (not the whole fraction)
jim_thompson5910
  • jim_thompson5910
look at how I wrote out f(x) in my first post
iwanttogotostanford
  • iwanttogotostanford
@jim_thompson5910 yes, true the negative i only applied to that
iwanttogotostanford
  • iwanttogotostanford
so would it be C or D
iwanttogotostanford
  • iwanttogotostanford
really need confirmation here
jim_thompson5910
  • jim_thompson5910
look at the answer choice that goes through (0,1)
anonymous
  • anonymous
oh ok i see now yes your right
iwanttogotostanford
  • iwanttogotostanford
i honestly can't tell from the graphs @jim_thompson5910
iwanttogotostanford
  • iwanttogotostanford
0,1 i would think A @jim_thompson5910
jim_thompson5910
  • jim_thompson5910
it can't be A because the lowest point on the left branch is somewhere in Q2
iwanttogotostanford
  • iwanttogotostanford
im so confused though did you look at the graphs i attached ?
jim_thompson5910
  • jim_thompson5910
yes I did
jim_thompson5910
  • jim_thompson5910
in choice A, the lowest point on the left upper branch is somewhere in Q1 when it should be somewhere in Q2
jim_thompson5910
  • jim_thompson5910
the graph looks like this |dw:1449459906459:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1449459937146:dw|
iwanttogotostanford
  • iwanttogotostanford
now i am thinking D, correct??? @jim_thompson5910
jim_thompson5910
  • jim_thompson5910
does the graph go through (0,1) in choice D ?
iwanttogotostanford
  • iwanttogotostanford
no, but i am really confused still and i really need the end result:-) please help
jim_thompson5910
  • jim_thompson5910
so it can't be choice D in choice D, hopefully you see how the y intercept is (0,-2) ?
iwanttogotostanford
  • iwanttogotostanford
ok, I've got that now
jim_thompson5910
  • jim_thompson5910
the y intercept of f(x) is (0,1) since plugging in x = 0 leads to the output of 1
iwanttogotostanford
  • iwanttogotostanford
ok, I've got that
iwanttogotostanford
  • iwanttogotostanford
so now i am thinking C because it has 0,1 more
jim_thompson5910
  • jim_thompson5910
yes, and C fits the shape and has that point I showed in the drawing in Q2
iwanttogotostanford
  • iwanttogotostanford
ok! great, could you help me with one more?
jim_thompson5910
  • jim_thompson5910
post it in a new post to avoid lag and clutter
iwanttogotostanford
  • iwanttogotostanford
ok, thanks ill tag u

Looking for something else?

Not the answer you are looking for? Search for more explanations.