PLZ H

- iwanttogotostanford

PLZ H

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- iwanttogotostanford

@jim_thompson5910

- jim_thompson5910

this is the function?
\[\Large f(x) = \frac{-x^2-2x-2}{x-2}\]

- iwanttogotostanford

yes! @jim_thompson5910

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## More answers

- jim_thompson5910

ok so you'll type in
`(-x^2-2x-2)/(x-2)`
into something like
https://www.desmos.com/calculator

- jim_thompson5910

make sure you zoom out so you can see the whole graph

- iwanttogotostanford

so when i type that in that is indefinitely my graph visually? @jim_thompson5910

- jim_thompson5910

there are 2 (disconnected) branches

- jim_thompson5910

yeah that's what the graph looks like

- iwanttogotostanford

two of my answers from my choices look similar but aren't the same

- iwanttogotostanford

@jim_thompson5910

- jim_thompson5910

how are they different?

- iwanttogotostanford

@jim_thompson5910 they are a tad different

- jim_thompson5910

can you show me?

- iwanttogotostanford

yea @jim_thompson5910

- jim_thompson5910

ok post a screenshot please

- iwanttogotostanford

sorry I'm getting it

- jim_thompson5910

that's ok, take all the time you need

- iwanttogotostanford

##### 1 Attachment

- iwanttogotostanford

here is the one that i think is correct

- iwanttogotostanford

would you say the same?

- anonymous

When i use the equation i dont get that

- iwanttogotostanford

what do u get?

- iwanttogotostanford

@hippo211

- iwanttogotostanford

could you draw the graph

- jim_thompson5910

@iwanttogotostanford what does the other graph look like?

- iwanttogotostanford

ok, ill give the answer choices and graphs

- anonymous

ok

- iwanttogotostanford

A.

##### 1 Attachment

- iwanttogotostanford

B.

##### 1 Attachment

- iwanttogotostanford

C.

##### 1 Attachment

- iwanttogotostanford

D.

##### 1 Attachment

- jim_thompson5910

if you plugged in x = 0, what would the value of f(0) be equal to?

- iwanttogotostanford

which of the graph choices would you say it is?

- jim_thompson5910

\[\Large f(x) = \frac{-x^2-2x-2}{x-2}\]
\[\Large f(0) = \frac{-(0)^2-2(0)-2}{0-2}\]
\[\Large f(0) = \underline{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }\]
fill in the blank

- iwanttogotostanford

i got -2/-2 but i think i did my algebra wrong

- jim_thompson5910

-2/-2 will reduce to 1

- jim_thompson5910

so f(0) = 1
this means that the point (0,1) is a point on the graph of f(x)

- iwanttogotostanford

yes, true

- jim_thompson5910

so use desmos to graph
and use the fact that (0,1) is on the graph

- iwanttogotostanford

so B would be the closest answer, correct?

- jim_thompson5910

did you use desmos to graph?

- iwanttogotostanford

yess

- jim_thompson5910

https://www.desmos.com/calculator/l7wpprkfxw

- iwanttogotostanford

now i am thinking C or D?

- anonymous

thats in wrong the way you enter the info

- anonymous

https://www.desmos.com/calculator/amezlkdjfr
look at this

- iwanttogotostanford

I'm very confused about which one it would be people

- iwanttogotostanford

A, B, C or D??you both are saying different answers

- jim_thompson5910

@hippo211 I think the first negative only applies to the x^2 (not the whole fraction)

- jim_thompson5910

look at how I wrote out f(x) in my first post

- iwanttogotostanford

@jim_thompson5910 yes, true the negative i only applied to that

- iwanttogotostanford

so would it be C or D

- iwanttogotostanford

really need confirmation here

- jim_thompson5910

look at the answer choice that goes through (0,1)

- anonymous

oh ok i see now yes your right

- iwanttogotostanford

i honestly can't tell from the graphs @jim_thompson5910

- iwanttogotostanford

0,1 i would think A @jim_thompson5910

- jim_thompson5910

it can't be A because the lowest point on the left branch is somewhere in Q2

- iwanttogotostanford

im so confused though did you look at the graphs i attached ?

- jim_thompson5910

yes I did

- jim_thompson5910

in choice A, the lowest point on the left upper branch is somewhere in Q1
when it should be somewhere in Q2

- jim_thompson5910

the graph looks like this
|dw:1449459906459:dw|

- jim_thompson5910

|dw:1449459937146:dw|

- iwanttogotostanford

now i am thinking D, correct??? @jim_thompson5910

- jim_thompson5910

does the graph go through (0,1) in choice D ?

- iwanttogotostanford

no, but i am really confused still and i really need the end result:-) please help

- jim_thompson5910

so it can't be choice D
in choice D, hopefully you see how the y intercept is (0,-2) ?

- iwanttogotostanford

ok, I've got that now

- jim_thompson5910

the y intercept of f(x) is (0,1)
since plugging in x = 0 leads to the output of 1

- iwanttogotostanford

ok, I've got that

- iwanttogotostanford

so now i am thinking C because it has 0,1 more

- jim_thompson5910

yes, and C fits the shape and has that point I showed in the drawing in Q2

- iwanttogotostanford

ok! great, could you help me with one more?

- jim_thompson5910

post it in a new post to avoid lag and clutter

- iwanttogotostanford

ok, thanks ill tag u

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