joshoyen
  • joshoyen
Simplify. 4+2i/-6i
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
The problem is this? \[\Large \frac{4+2i}{-6i}\]
joshoyen
  • joshoyen
Yes
jim_thompson5910
  • jim_thompson5910
Multiply the fraction by \(\Large \frac{i}{i}\) \[\Large \frac{4+2i}{-6i}*\frac{i}{i} = ??\]

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More answers

jim_thompson5910
  • jim_thompson5910
\(\Large \frac{i}{i}\) is equal to 1. When we multiply any expression by 1, it doesn't change.
joshoyen
  • joshoyen
wait so do you multiply i/i for every problem?
jim_thompson5910
  • jim_thompson5910
to turn the denominator into a real number, yes
jim_thompson5910
  • jim_thompson5910
only if you have something in the form k*i in the denominator k is any real number
jim_thompson5910
  • jim_thompson5910
to take advantage of the fact that i*i = i^2 = -1
joshoyen
  • joshoyen
Wait im still a bit confused whatss the next step after 4+2i/−6i ∗ i/i
jim_thompson5910
  • jim_thompson5910
\[\Large \frac{4+2i}{-6i}*\frac{i}{i} =\frac{(4+2i)*i}{-6i*i} = ??\]
jim_thompson5910
  • jim_thompson5910
you'll have to use the distributive property
joshoyen
  • joshoyen
so its -4-2i / 6 ?
jim_thompson5910
  • jim_thompson5910
(4+2i)*i = 4i + 2i^2 = 4i+2(-1) = 4i-2
jim_thompson5910
  • jim_thompson5910
So we have \[\Large \frac{4i-2}{6}\] then we can do a bit of factoring \[\Large \frac{4i-2}{6}=\frac{2(2i-1)}{2*3}\] I'm sure you see what would cancel
joshoyen
  • joshoyen
hmm okay, thanks
jim_thompson5910
  • jim_thompson5910
no problem
joshoyen
  • joshoyen
How would I do 2/-6i ?
joshoyen
  • joshoyen
i'm still confused on this..

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