• seb.cal
Please check my work :) Question: How many milliliters of calcium, with a density of 1.55 g/mL, are needed to produce 98.5 grams of calcium hydroxide in the single-replacement reaction below? Show all steps of your calculation as well as the final answer. Ca + H2O → Ca(OH)2 + H2 My Answer: Balanced Equation: Ca + 2 H2O → Ca(OH)2 + H2 The Math: 98.5 g Ca(OH)2 over 74.0932 g/mol times (1 over 1) times 40.0784 g/mol over 1.55 g/mL = 34.4 mL Calcium.
Mathematics
• Stacey Warren - Expert brainly.com
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