benlindquist
  • benlindquist
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Mathematics
  • Stacey Warren - Expert brainly.com
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benlindquist
  • benlindquist
benlindquist
  • benlindquist
(x + 4, y + 3) (x + 3, y + 4) (x - 3, y - 4) (x - 4, y - 3
benlindquist
  • benlindquist
How would you figure this out?

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More answers

iGreen
  • iGreen
T = (-3, -2) T' = (0, 2)
iGreen
  • iGreen
Find out what you have to add/subtract to -3 to get 0, and what you have to add/subtract from -2 to get 2.
benlindquist
  • benlindquist
Would it be (x - 3, y - 4)
anonymous
  • anonymous
yes
benlindquist
  • benlindquist
ok
iGreen
  • iGreen
No, -3 - 3 does not equal 0
iGreen
  • iGreen
It equals -6
benlindquist
  • benlindquist
Cause you add them
iGreen
  • iGreen
And -2 - 4 is -6, not 0
iGreen
  • iGreen
not 2*
anonymous
  • anonymous
no -3 and 3 is 0
benlindquist
  • benlindquist
You are seeing -3 and 3 don't you add them?
iGreen
  • iGreen
Yes, you add 3 to -3 to get 0.
iGreen
  • iGreen
So you add 3 to the x. \(\sf (x + 3,~?)\)
iGreen
  • iGreen
Now what do you add or subtract from -2 to get 2?
benlindquist
  • benlindquist
Subtract?
iGreen
  • iGreen
-2 + x = 2 Can you solve that for 'x'?
benlindquist
  • benlindquist
it would be 0
iGreen
  • iGreen
No..how did you get that? Add 2 to both sides.
benlindquist
  • benlindquist
So 2 + x = 4
benlindquist
  • benlindquist
(x - 4, y - 3)
iGreen
  • iGreen
-2 + 2 doesn't equal 2
benlindquist
  • benlindquist
weird its 0
iGreen
  • iGreen
Yes, so that gives us: x = 4
iGreen
  • iGreen
So we ADD 4 to the y-value, giving us: \(\sf (x + 3, x + 4)\)
iGreen
  • iGreen
\(\sf y + 4*\)
benlindquist
  • benlindquist
so the answer would be (x + 4, y + 3)
iGreen
  • iGreen
No, it's the other way around. \(\sf (x + 3, y + 4\)
benlindquist
  • benlindquist
ok

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