Please help me, I don't understand this...
How many grams of aluminum chloride must decompose to produce 78.3 milliliters of aluminum metal, if the density of aluminum is 2.70 g/mL? Show all steps of your calculation as well as the final answer.
AlCl3 → Al + Cl2
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
1. Ask your teacher because this is soemthing you will face often in chem.
2. what is the density of cl?
you have to take the density of al+cl+cl and find how much alcl2 it takes to create 78.3 ml of al
you need to add the densities together
what is the denisty provided for cl?
You must start with a balanced chemical equation:
2AlCl3 → 2Al + 3Cl2
???g ......78.3 mL
Use the volume and density to get the mass, and then the number of moles of Al, and then the moles of Al2O3 (it will be the same, since the mole ratio is 1:1) and finally convert the moles of AlCl3 to grams of AlCl3.
78.3 mL x (2.70g Al / 1 mL) x (1 mol Al / 27.0g Al) x (1 mol AlCl3 / 1 mol Al) x (133.5 g AlCl3 / 1 mol AlCl3) = 1045 g AlCl3