karamarie02
  • karamarie02
WILL FAN AND MEDAL!!!!! Evaluate the expression, using the given value of the variable. z ÷ 2 – 4z + 3(z – 3) when z = 8 A. 17 B. 13 C. 7 D. 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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flamingpiano
  • flamingpiano
That would become 8/2-32+3(8-3), do you know how to solve it from there?
karamarie02
  • karamarie02
@flamingpiano No...still confused on it.
anonymous
  • anonymous
i'll help

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anonymous
  • anonymous
they have already provided the given value so we just need to plug it in
anonymous
  • anonymous
hold on one sec
karamarie02
  • karamarie02
@LGumboymath234 im still confused on the answer tho.
flamingpiano
  • flamingpiano
Here, let's go one step further. 8/2-32+3(8-3), take the (8-3)=5, then you do 5*3, giving you 15. So now you have 8/2-32+15.
flamingpiano
  • flamingpiano
Now you divide 8/2, giving you 4-32+15, can you do that?
anonymous
  • anonymous
-13
flamingpiano
  • flamingpiano
Yep.
karamarie02
  • karamarie02
so -13 is the correct answer?
flamingpiano
  • flamingpiano
@karamarie02 , I messed up somewhere that made it -, do you know where?
flamingpiano
  • flamingpiano
@LGumboymath234 , Do you know where the mistake is?
karamarie02
  • karamarie02
no
flamingpiano
  • flamingpiano
Hmm, I just worked it out again, it gave me -13 in a calculator. Maybe it wants you to multiply by -1 to give you 13?
flamingpiano
  • flamingpiano
So I'd say it'd have to be B. 13
karamarie02
  • karamarie02
okay... Can you help me with one ore question? @LGumboymath234 and @flamingpiano
flamingpiano
  • flamingpiano
Sure.
karamarie02
  • karamarie02
What is when n = 8?
flamingpiano
  • flamingpiano
Is there an equation? All I see is "What is when n = 8?"
karamarie02
  • karamarie02
wait one second please.
karamarie02
  • karamarie02
What is (n-5) x 6 / n divided by 4 when n = 8?
flamingpiano
  • flamingpiano
It would simplify to (8-5)*6/8, then to 3*6/8 giving you 2.25.
karamarie02
  • karamarie02
thankyou!!!!!!
flamingpiano
  • flamingpiano
You're welcome.

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