blake57roger
  • blake57roger
A right triangle has one leg that measures 12 inches and a hypotenuse that measures 13 inches. Enter the area, in square units, of the triangle.
Mathematics
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SOLVED
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chestercat
  • chestercat
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Bookworm14
  • Bookworm14
@Agl202 @goformit100 @Nnesha @ParthKohli @TheSmartOne @whpalmer4 Is there any way any of you could help him please? I don't have time at the moment. Thank you so much in advance!
Nnesha
  • Nnesha
formula to find area of right triangle is \[\large \rm A=\frac{1}{2} b*h\] where b is base and h is height
Nnesha
  • Nnesha
and it's a right triangle so to find missing side you can use Pythagorean theorem a^2+b^2=c^2 where c is the longest side of right triangle (hypotenuse )

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More answers

blake57roger
  • blake57roger
25
blake57roger
  • blake57roger
is A^2 + B^2= C^2
Nnesha
  • Nnesha
what's 25 ??
blake57roger
  • blake57roger
5
Nnesha
  • Nnesha
correct that's the 3rd side now just use the formula to find area of right triangle
blake57roger
  • blake57roger
30
blake57roger
  • blake57roger
is that the answer
Nnesha
  • Nnesha
how did you get that ?
blake57roger
  • blake57roger
0.5*5*12
blake57roger
  • blake57roger
1/2*5*12
Nnesha
  • Nnesha
then yes that's correct
blake57roger
  • blake57roger
thanks
Nnesha
  • Nnesha
remember it should be in `square ` units and np :=))
blake57roger
  • blake57roger
@Nnesha
blake57roger
  • blake57roger
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whpalmer4
  • whpalmer4
You need the formula for distance between two points \((x_1,y_1)\) and \((x_2,y_2)\): \[d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\] You know one of the points, and you can find the other by counting marks on the graph from the origin. Doesn't matter which point you call \((x_1,y_1)\) and which point you call \((x_2,y_2)\). This is just the Pythagorean theorem in disguise...the hypotenuse is the distance.

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