anonymous
  • anonymous
Fan and medal :) Which equation represents the line that passes through the points (6,-3) and (-3,-9)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Please explain and help me through it
pooja195
  • pooja195
First you need to find the slope using the slope formula \[\LARGE \frac{y_2-y_1}{x_2-x_1}=slope\]
anonymous
  • anonymous
I'm thinking it's y+4=3/5(x+6)

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anonymous
  • anonymous
Wait so Y^2=6 y^1=-3/x^2=-4 - x^1=9?
anonymous
  • anonymous
idk if that's right lol
pooja195
  • pooja195
Ok that's incorrect from what i can tell.... \[\huge y-y_1=m(x-x_1)\] where m=slope (x1,y1)
anonymous
  • anonymous
What are y?
anonymous
  • anonymous
Is that the right number (6,-3) (3)
pooja195
  • pooja195
Lable your x1 y1 and slope
anonymous
  • anonymous
Mkay
anonymous
  • anonymous
How do I do that :D
anonymous
  • anonymous
I forget haven't done this in forever
pooja195
  • pooja195
What is the slope?
anonymous
  • anonymous
I literally just got done with a 50 question star test my brain is fried
pooja195
  • pooja195
\[\LARGE \frac{y_2-y_1}{x_2-x_1}=slope\] \[\LARGE \frac{-9+3=?}{-3-6=?}=slope\]
anonymous
  • anonymous
WHAT! ok, where's is the +3?
anonymous
  • anonymous
Did you get that from another number that's isn't in the equation
pooja195
  • pooja195
when you have 2 negatives together they become positive \[\LARGE \frac{y_2-y_1}{x_2-x_1}=slope\] \[\LARGE \frac{-9--3}{-3-6}=slope\] \[\LARGE \frac{-9+3=?}{-3-6=?}=slope\]
anonymous
  • anonymous
-9+3=-6 -3-6 = -9
anonymous
  • anonymous
Mkay I understand the negative together makes positive starting to understand now lol
pooja195
  • pooja195
Good now simplify that
anonymous
  • anonymous
Wait what? how do I simplify that My gosh i'm bad at this
anonymous
  • anonymous
I bet you're thinking i'm dumb right now huh?
anonymous
  • anonymous
I'm literally like dead by laughing from this almost fell out of my chair haha
pooja195
  • pooja195
|dw:1449519709453:dw|
anonymous
  • anonymous
Oh divide?
pooja195
  • pooja195
Pretty much now we have our slope m=-4/3 x1=6 y1=-3 Now... \[\huge y-y_1=m(x-x_1)\] where m=slope (x1,y1)
pooja195
  • pooja195
Plug in the numbers to get your answer
anonymous
  • anonymous
-4/3 is 1.333
pooja195
  • pooja195
Done divide leave it as a fraction
pooja195
  • pooja195
I need to get to my next class @jabez177 or @KendrickLamar2014 can help u :)
pooja195
  • pooja195
Sorry!
anonymous
  • anonymous
6-x^1=
anonymous
  • anonymous
Wait class?
anonymous
  • anonymous
Oh you're a teacher my bad ok sorry see yah
anonymous
  • anonymous
Lamar
anonymous
  • anonymous
Yo, What's happening?
KendrickLamar2014
  • KendrickLamar2014
I have to go to. @jabez177 can probably help you
anonymous
  • anonymous
Really dude
anonymous
  • anonymous
Are you a teacher aswell?
anonymous
  • anonymous
I got the answer y+3=3/5(x-6)
anonymous
  • anonymous
I need help with one more please it's a graph and I'm bad with them so if anybody is there please help!
jabez177
  • jabez177
I have to go also... Sorry!!!
anonymous
  • anonymous
Guys, Stop leaving and just help me with one question I know you have a little bit of time you can't be having to go it's literally 2:33 unless you started a class at 2:30 com'n Sorry just had to say it
jabez177
  • jabez177
I am so sorry!!! I had to go get a blood test so I didn't have any time at all. :P

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