anonymous
  • anonymous
An equation in point slope form, standard form, and slope-intercept form. for the line that passes through (0, -2), (3, 2). Will fan and medal
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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563blackghost
  • 563blackghost
First we would find the slope so use the slope formula... \[\frac{ y2-y1 }{ x2-x1 }\]
563blackghost
  • 563blackghost
We input the points and subtract and would get the slope...
anonymous
  • anonymous
Yes. Ok so the slope would be 1 and 1/3rd.

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563blackghost
  • 563blackghost
Incorrect.....\[\frac{ 2--2 }{ 3-0 }\] Remember that when subtracting a negative that you are practically adding so it would turn to 2 + 2....\[\frac{ 2+2 }{ 3-0 }\]
anonymous
  • anonymous
3-0 = 3... 4/3 = 1.33333 so 1 and 1/3 or 4/3 if you want to call it that.
563blackghost
  • 563blackghost
Yup it would be 4/3 ^^ Now lets input that in slope-intercept form...\[y=mx+b\] So m is the slope and b is the y-intercept...now the y-intercept is where we know y while x is 0 so (0,#)....do we know the y-intercept?
anonymous
  • anonymous
Wouldn't the Y intercept just be either, -2 or 2?
563blackghost
  • 563blackghost
it would be -2 xD so how would the equation look like?
anonymous
  • anonymous
-2 = 4/3 * 0 + B
563blackghost
  • 563blackghost
Incorrect.... remember x will stay x and the y-intercept goes where b is...
anonymous
  • anonymous
Uh, ok so B is -2?
563blackghost
  • 563blackghost
yup ^^
anonymous
  • anonymous
So, y = 4/3 * 0 + -2
563blackghost
  • 563blackghost
Correct! so...\[y=\frac{ 4 }{ 3 }x-2\]
563blackghost
  • 563blackghost
Now lets get point slope form.... Now for point slope we must know the first coordinates and the slope which we know of so we would input it into the equation....\[y-y1=m(x-x1)\]
anonymous
  • anonymous
ok, what we just did was slope intercept form right
563blackghost
  • 563blackghost
Correct ^^
anonymous
  • anonymous
Ok.. So, can you explain the point slope a bit more thoroughly?
563blackghost
  • 563blackghost
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anonymous
  • anonymous
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anonymous
  • anonymous
is what i circled x2?
563blackghost
  • 563blackghost
if you mean (x-2) then yes but its not "x2"
anonymous
  • anonymous
y-0 = m(x-2) ?
563blackghost
  • 563blackghost
Wait! I explained it wrong I am so sorry....the x-intercept is acutally 0 plz forgive me... So the point-slope form is...\[y+2=\frac{ 4 }{ 3 }(x-0)\]
anonymous
  • anonymous
Ok, is that a complete point slope form then? Or do we have to figure out the remaining variables?
563blackghost
  • 563blackghost
That is the complete point-slope form....but Idk how to change to standard-form sorry....:(
anonymous
  • anonymous
Haha I don't even know what a standard form intercept thing is :P. Thanks for all your help though, I'll bump it and see if anyone knows how to make it standard. TY!
563blackghost
  • 563blackghost
Glad I was of help ^^
563blackghost
  • 563blackghost
if i figure it out ill txt u xD
563blackghost
  • 563blackghost
\[y=\frac{ 4 }{ 3 }x-2\] we switch this equation around... \[-\frac{ 4 }{ 3 }x+y=-2\] we need to get 4/3 as a whole number so we multiply 3 with -4/3x and y\[4x-3y=2\]
563blackghost
  • 563blackghost
GOT IT XD
anonymous
  • anonymous
Haha ty!

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