anonymous
  • anonymous
Probability Inquiry!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
`A box contains eight 40-W bulbs, nine 60-W bulbs, and seven 75-W bulbs. If bulbs are selected one by one in random order, what is the probability that at least two bulbs must be selected to obtain one that is rated 75 W?` The correct solution that I obtained was: \[\text{P}(A)=1-\text{P}(\bar{A})=1-\frac{ 7 }{ 7+9+8 }=0.708\]My question is -- how does the `at least two bulbs` factor into this solution? What if it was at least three or four bulbs?
Vocaloid
  • Vocaloid
let P(A) be equal to the probability of getting the bulb on the first try then 1 - P(A) is equal to the probability of NOT getting the bulb on the first try (AKA, at least 2 bulbs are necessary) @CShrix does that make sense?
Vocaloid
  • Vocaloid
to answer your second question, we would use the same process for 3 or 4 or whatever number of bulbs you want for example: the probability of needing at least 3 bulbs = 1 - probability of getting it on the first try - probability of getting it on the second try

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anonymous
  • anonymous
Ahh! Yes that makes sense now. Thank you X)

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