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Not a quadrilateral, just a curved four sided thing in the middle
yes. The actual goal is to find the overlapping areas where the circle portions overlap each other, but if i get the center area, I think i can calculate the rest.
Ok, so you want these areas? |dw:1449528016942:dw|
yes, preferably but whichever area is easier was my initial goal.
In other words, with the area of the center piece, i can get the areas of those overlaps
brb, let me try a few things
i'm really sorry, shoulda clarified, it's a circle with one-fourth of its radius in the square. I didn't think that was relevant
but if i can treat it as an ellipse and get the same answer that should be fine actually
Subtract out area of triangle from area of sector to get the area of circular section inside: |dw:1449530698995:dw|
and then if i multiply that area by 4, I get an overcount
Check this out...
that would give the area of the outside portions whilst counting the overlap only once i think
Seems like there is an inconsistency with the problem. In order to have a side equal to 2 and a circle of radius 2, then the distance \(x\) needs to be 1.322 not 1: |dw:1449535226592:dw| |dw:1449535462949:dw|
would it be correct if 0.5 was one fourth of the diamter instead?
Still inconsistent: |dw:1449535868469:dw|
Are the sides really 2?
My prof is honestly a little weird. here's what i have accumulated thus far:|dw:1449536068242:dw|
So the side is sqrt(3) not 2?
well, the side has to be sqrt(3) times the radius of the circle, it must be. I'm going to disregard his silly measurements
Yes, that is the length of the chord you've drawn, but that's the problem you setup
if i let r=2 for his purposes, i'm still faced with the same issue
That IS the area of the triangle, though
I'm confused about what the problem is now
Same exact picture, I need to find the area of the little overlaps
I have the area of the sector portions ALONE, but i need another piece of information
makes more sense now