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1/3 2/3 1/6 5/6
Let me tell you why
thats my name btw :0
See how many of the 6 possible outcomes are the ones you want.
How many numbers on the dice are greater than 4? 3 How many of them are even AND less than 4? 1 Add those two answers and put it over 6. Simplify and the answer is there
it is 2,4,5, and 6 because greater than 4(5 and 6) and (even(2,4,6) 6 repeats, so 2,4,5,6 is 4/6=2/3
i got 2/3
i have another one just like it can u help me with it?
2/3 is correct.
You roll a 6-sided die with faces numbered 1 through 6, and toss a coin. What is the probability of rolling a 5 or getting tails? A. B. C. D.
1/3 7/12 3/4 1/12
So, you only want to roll a 5, which is 1 number. So put 1 over 6 to get 1/6. That's the dice possibility. Ofc, two sides to a coin so it's always 50/50, or 1/2. Then because you're doing both, you would multiply the denominators to get 12 I would first put them both in terms of 12, so it will be easier 1/12 and 6/12, instead of 1/6 and 1/2 So, now add the 1/12 and 6/12 together to get your answer
wait 2kende are you here still?
I think I caught a mistake
1/6 is 2/12 and 1/2 is 6/12
damn.. ):but its too late i already submitted the question
can you help me with this next one?
Find the missing probability in the table below. X 1 2 3 4 P(X) 0.40 0.20 0.15 ? A. 0.25 B. 0.75 C. 0.85 D. 0.15
@OpenStudy9 Ahh, I just noticed it also. Good find. My mistake @2kende
So there is a pattern in this question
first, subtract .2, then .5
i added them all together and got .75
the question asks for the missing value right?
yes, the missing probability
IS that all in the question?
It could be a quadratic, lt me take a closer look
are those the right numbers?
Is this "quiz" timed?
i think it could be D
Can you come back to problems? If not, go with D
no i cant go back
the go with D for now;)
ok, do u have time for a couple more?
maybe one more
What is it?
Given the table of candy distributions below, find P(Not orange), the probability of selecting anything but an orange candy at random from a large bag. Red Orange Yellow Green Blue Brown 0.13 0.20 ? 0.16 0.24 0.13 A. 0.80 B. 0.20 C. 0.70 D. 0.50
You typed this very confusing
Where is the question mark?
the question mark is the missing yellow color
thats what were trying to find
ok, the rest go as folows, got it, one sec..
Let me tell you why
All must add up to 1
yellow is .14
orange is .2
1-.2 is .8
You still there?
ohhh i get it
Your welcome! No biggie, but do you mind giving me a medal?
1 more please?
Bring it on!
Given the Venn diagram below, if a student is randomly selected, what is the probability that he or she is not attending both colleges? A. 86% B. 82% C. 80% D. 84%
I think i almost got it..
28 are attending both colleges
They all add up to 200
(200-28)/200=.86 Hence, 86 percent
i got a 90% <3 thanks
probably, the one that the forty rapper guy missed, and 2 others
lol yea, but im glad u came through (: