anonymous
  • anonymous
A Math 148 student set three clocks with different snooze alarms. Clock A goes off every 15 minutes, clock B every 40 minutes, and clock C every 45 minutes. If all three clocks go off at 6:00 am, how long will it be for all three clocks to go off simultaneously after that time?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Find the LCM of 15, 40 and 45 Then calculate the time....
anonymous
  • anonymous
wouldn't that by 5?
anonymous
  • anonymous
be*

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anonymous
  • anonymous
no that is their HCF.. You have to find the Lowest Common MULTIPLE.......
anonymous
  • anonymous
so multiply each number until you get the same number for all three?
anonymous
  • anonymous
that is the longer method. Don't you know the ladder division method??
anonymous
  • anonymous
nope
anonymous
  • anonymous
which standard/class r u in??
anonymous
  • anonymous
I'm in college. But thats common core so I've never had to use it
anonymous
  • anonymous
ok, then write tables of each number till you find the first common multiple
retirEEd
  • retirEEd
Don't feel lonely, I have a masters in engineering and I never heard of the ladder division method. Time for google.
anonymous
  • anonymous
15, 30, 45, 60, 75, 90, --------- 40, 80, 120, 160, --------- 45, 90, 135, 180, ---------
anonymous
  • anonymous
|dw:1449530105537:dw| further steps in nest pic..
anonymous
  • anonymous
|dw:1449530221791:dw|
anonymous
  • anonymous
So, LCM of 15, 40, 45 = 2 x 2 x 2 x 3 x 3 x 5 = 360
anonymous
  • anonymous
so in 6 hours it will go off again all at the same time?
retirEEd
  • retirEEd
That's cool!
anonymous
  • anonymous
yes, correct... 360 minutes = 6 hrs and 6 hrs after 6:00 am will be 12 noon
anonymous
  • anonymous
I guess my "ladder division method" might be known to you as Prime Factorisation Method"
anonymous
  • anonymous
Oh. see i know that word XD
anonymous
  • anonymous
thank you!

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