What volume in L of oxygen is required to burn 0.556L of propane if both gases are measured at the same temperature and pressure?
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What is the formula for propane, and what is the balanced equation for the reaction?
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C3H8 + 5O2 ----> 3CO2 + 4H2O
ok, good. what do we know about moles of gas at the same temperature and pressure?
Avogadro's law says equal volumes of all gases, at the same temperature and pressure, have the same number of molecules. That means we just need to figure out the ratio of moles of oxygen to moles of propane and then apply that same proportion to the quantity of propane we are burning.
If 1 mole of one of the reactants takes up x liters of space, then 2 moles of that reactant will take up 2x liters, and so on.
dont solve it.
I am working on it now.
Not my final answer. Those moles for propane doesn't look right?
Is that even right? That number seems very small..
2.78L of O2
My mole ratio was backwards
We need 5 moles of O2 for every 1 mole of propane, so if we have 0.556 L of propane, we need 5*0.556 = 2.78 L of O2.