raffle_snaffle
  • raffle_snaffle
What volume in L of oxygen is required to burn 0.556L of propane if both gases are measured at the same temperature and pressure?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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raffle_snaffle
  • raffle_snaffle
@whpalmer4
whpalmer4
  • whpalmer4
What is the formula for propane, and what is the balanced equation for the reaction?
raffle_snaffle
  • raffle_snaffle
C3H8

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More answers

raffle_snaffle
  • raffle_snaffle
C3H8 + 5O2 ----> 3CO2 + 4H2O
whpalmer4
  • whpalmer4
ok, good. what do we know about moles of gas at the same temperature and pressure?
whpalmer4
  • whpalmer4
Avogadro's law says equal volumes of all gases, at the same temperature and pressure, have the same number of molecules. That means we just need to figure out the ratio of moles of oxygen to moles of propane and then apply that same proportion to the quantity of propane we are burning.
whpalmer4
  • whpalmer4
If 1 mole of one of the reactants takes up x liters of space, then 2 moles of that reactant will take up 2x liters, and so on.
raffle_snaffle
  • raffle_snaffle
dont solve it.
raffle_snaffle
  • raffle_snaffle
I am working on it now.
raffle_snaffle
  • raffle_snaffle
Not my final answer. Those moles for propane doesn't look right?
raffle_snaffle
  • raffle_snaffle
Is that even right? That number seems very small..
raffle_snaffle
  • raffle_snaffle
2.78L of O2
raffle_snaffle
  • raffle_snaffle
My mole ratio was backwards
whpalmer4
  • whpalmer4
We need 5 moles of O2 for every 1 mole of propane, so if we have 0.556 L of propane, we need 5*0.556 = 2.78 L of O2.

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