• harvey03
How would I work out 'Calculate the mass of iron formed from 8g of iron (III) oxide, Fe2O3: (Ar values: Fe=56, O=16)?
  • Stacey Warren - Expert brainly.com
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  • jamiebookeater
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  • anonymous
First write equation and balance it, to find ratio of moles.\[2Fe _{2}O _{3}\rightarrow 4Fe+3O _{2}\] As you can see , the ratio between Fe2O3 and Fe is 2:4 or 1:2. What you do now is find the mol of 8 g wanted in question. That can be calculated by the formula\[mol=\frac{ Given Mass }{ MolarMass }=\frac{ 8 }{ 56(2)+16(3) }=0.05mol\] By ratio and proportion, 0.05*2/1=0.1mol of Fe\[GivenMass=mol*MolarMass=0.1*56=5.6g\]

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