anonymous
  • anonymous
What is the common difference between successive terms in the sequence? 9, 2.5, –4, –10.5, –17, ... –11.5 –6.5 6.5 11.5
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
(a term) - (term before) = (difference)
anonymous
  • anonymous
So if we use the following notations, \(a_n\) - some Nth term. \(a_{n+1}\) - some term which is right after the Nth term. \(d\) - common differnce Then, the "difference" is by definition, \(a_{n+1}-a_n=d\)
Cal.lavender
  • Cal.lavender
(a_n=a_1+(n-1)d a_2 implies 2.5=9+(1)d 2.5-9=d -6.5=d

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
However, \(a_{n+1}-a_n=d\) Has to give you the same difference for all n, and if that is not the case, then your sequence is not an arithmetic sequence (if is a sequence at all), and no common difference is going to exist. (How can there be a common differnce if the difference varies?)

Looking for something else?

Not the answer you are looking for? Search for more explanations.