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  • freemap
Please help me
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
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1 Attachment
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Question 2
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  • freemap
@Michele_Laino

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Michele_Laino
  • Michele_Laino
hint: domain of a function is given by the set of all value of the independent variable. In your exercise, the independent variable is represented by the number of days
Michele_Laino
  • Michele_Laino
values*
Michele_Laino
  • Michele_Laino
sorry, I have to study question #2
freemap
  • freemap
100 every week would be $100. $400 in 4 weeks $500 in 5 weeks $600 in 6 weeks. The last day her balance was $400 was Day 8. Wait I don't get it
Michele_Laino
  • Michele_Laino
hint: from the text of the exercise, the maximum balance holds from day #4 to day #8 now days #5, #6 and #7 are inside such interval, so, what can you conclude?
freemap
  • freemap
i don't know. I don't get it starts with $400 and end with $400
Michele_Laino
  • Michele_Laino
so we can write this: \(B(5)=B(6)=B(7)=400\), am I right?
freemap
  • freemap
I guess if see ends with $400
Michele_Laino
  • Michele_Laino
|dw:1449589049644:dw|
freemap
  • freemap
I get it now
Michele_Laino
  • Michele_Laino
ok! Now, we can see that the balance at day zero (starting day) is \($200\) |dw:1449589235279:dw|
freemap
  • freemap
I see
Michele_Laino
  • Michele_Laino
ok! :) Next I have to write the equation of the line which passes at point M and at point Q: |dw:1449589413319:dw|
Michele_Laino
  • Michele_Laino
the coordinates of popints M and Q, are: \(M=(0,200)\), \(Q=(4,400)\), so the slope \(m\) of such line is: \[m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} = \frac{{400 - 200}}{{4 - 0}} = ...?\]
Michele_Laino
  • Michele_Laino
oops.. the coordinates of points* M and Q...
freemap
  • freemap
200/4=50
Michele_Laino
  • Michele_Laino
that's right!
Michele_Laino
  • Michele_Laino
now we have to apply the subsequent equation: \(y-y_0=m(x-x_0)\) where, for example the point \((x_0,y_0)=M=(0,200)\) what do you get?
freemap
  • freemap
just a sec
freemap
  • freemap
200-400=0-200
Michele_Laino
  • Michele_Laino
no, please note that, after a substitution, I get this: \(y-200=50(x-0)\) please simplify
freemap
  • freemap
y-200=50x-50 150=50x 3
Michele_Laino
  • Michele_Laino
hint: I get this equation: \(y=50x+200\) am I right?
freemap
  • freemap
yes
Michele_Laino
  • Michele_Laino
such equation describes the balance between day #0 and day #4, so we can write this: \(B(1)=50 \cdot 1+200=...?\) \(B(2)=50 \cdot 2+200=...?\) \(B(3)=50 \cdot 3+200=...?\)
freemap
  • freemap
250 300 350
Michele_Laino
  • Michele_Laino
that's right!
freemap
  • freemap
How do we start C
Michele_Laino
  • Michele_Laino
it is simple, since between days #0, and #4 the balance goes from $200 and $400 and the balance change is \(400-200=...?\), whereas between days #8 and #12 the balance goes from 400 to 0 and the corresponding balance change is \(400-0=...?\)
freemap
  • freemap
400
Michele_Laino
  • Michele_Laino
whereas the first balance change is \(400-200=...?\)
freemap
  • freemap
200
Michele_Laino
  • Michele_Laino
right! and as we can see, such balance changes are different each from other
Michele_Laino
  • Michele_Laino
here is why Jade is wrong
freemap
  • freemap
shes wrong because balance changes are different from each other and not the same
Michele_Laino
  • Michele_Laino
yes!
freemap
  • freemap
Thank you
Michele_Laino
  • Michele_Laino
:)

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