stuck-help
  • stuck-help
can anyone help balencing equations in the comments
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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stuck-help
  • stuck-help
hold on i meesed up
stuck-help
  • stuck-help
|dw:1449597609108:dw|
stuck-help
  • stuck-help
@Michele_Laino

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Michele_Laino
  • Michele_Laino
is your reaction, like this: \[\Large {\text{Zn + H}}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{3}}}{{\text{O}}_{\text{2}}} \to {\text{Zn}}\left( {{\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}} \right){\text{ + }}{{\text{H}}_{\text{2}}}\]
stuck-help
  • stuck-help
\[Zn+HC _{4}H _{3}O _{2}\rightarrow ZN(cH _{3}Coo)_{2}+H _{2}\]
stuck-help
  • stuck-help
so no H after Coo
Michele_Laino
  • Michele_Laino
sorry, I understand: \[\Large {\text{Zn + H}}{{\text{C}}_{\text{4}}}{{\text{H}}_{\text{3}}}{{\text{O}}_{\text{2}}} \to {\text{Zn}}{\left( {{\text{C}}{{\text{H}}_{\text{3}}}{\text{COO}}} \right)_{\text{2}}}{\text{ + }}{{\text{H}}_{\text{2}}}\]
stuck-help
  • stuck-help
ok yes that is it
Michele_Laino
  • Michele_Laino
please wait I'm working on your question...
stuck-help
  • stuck-help
ok thanks
Michele_Laino
  • Michele_Laino
I'm very sorry, I don't know how to balance such chemical reaction
Michele_Laino
  • Michele_Laino
@chmvijay please can you help here?
Michele_Laino
  • Michele_Laino
@jigglypuff314 please can you help here?
jigglypuff314
  • jigglypuff314
to my knowledge on how to balance equations, I don't believe it is possible... on the left you have 1 Zn 4 H 4 C 2 O and on the right you have 1 Zn 8 H 4 C 4 O because of how they are connected to each other, no matter what coefficients you try to add, it won't even out :-/ I can't help, sorry.
jigglypuff314
  • jigglypuff314
wait... please recheck that is the correct equation? \[\Large {\text{Zn + H}}{{\text{C}}_{\text{4}}}{{\text{H}}_{\text{3}}}{{\text{O}}_{\text{2}}} \to {\text{Zn}}{\left( {{\text{C}}{{\text{H}}_{\text{3}}}{\text{COO}}} \right)_{\text{2}}}{\text{ + }}{{\text{H}}_{\text{2}}}\]
stuck-help
  • stuck-help
wait it is not that first 4 is suppose to be a 2
jigglypuff314
  • jigglypuff314
ohhh that fixes it on the left you have 1 Zn 4 H 2 C 2 O and on the right you have 1 Zn 8 H 4 C 4 O if you compare them you can see that the right side's (H) is the left side times 2 the right side's (C) is the left side times 2 and the right side's (O) is the left side times 2 that means that all you need to do is add a \(2\) in front of the \((H C_2 H_3 O_2)\)
stuck-help
  • stuck-help
ok so the balanced equation would be \[Zn+2(HC _{2}H _{3}O _{2}) \rightarrow Zn(cH _{3}Coo)_{2}+H _{2}\]
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@jigglypuff314
jigglypuff314
  • jigglypuff314
yes

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