anonymous
  • anonymous
The region in the first quadrant bounded by the x-axis, the line x = π, and the curve y = sin(sin(x)) is rotated about the x-axis. What is the volume of the generated solid?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
https://gyazo.com/9ccb696779c5a1339d9c084cfe54d9e5 @freckles
anonymous
  • anonymous
@Zarkon
anonymous
  • anonymous
@IrishBoy123

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anonymous
  • anonymous
\[\int\limits_{0}^{\pi} \pi[\sin(\sin (x))]^2 dx \]
anonymous
  • anonymous
\[A(x)=\pi r^2\]
anonymous
  • anonymous
I am getting 5.435 x 10^-5 Which is obviously wrong
anonymous
  • anonymous
@zepdrix Are you aware of what must be done for this question?
zepdrix
  • zepdrix
Sec, lemme see if I can work it out :)
anonymous
  • anonymous
Ok thanks
zepdrix
  • zepdrix
Hmm your integral looks correct :o Where did you get the numerical value from? I don't think this integral has a nice closed-form solution. So I guess you have to use some type of algebra calculator or something? Wolfram seems to give us the correct answer: https://www.wolframalpha.com/input/?i=integral+of+pi+sin%5E2%28sinx%29+from+x%3D0+to+x%3Dpi
anonymous
  • anonymous
I used my calculator to save me some time.
zepdrix
  • zepdrix
Ya you would have to do that for this problem :) Maybe some trouble inputting it with your brackets and all that? Cause your setup looks good.
anonymous
  • anonymous
I entered it as above
anonymous
  • anonymous
Maybe the way you entered it into wolfram is more appropriate, let me try.
zepdrix
  • zepdrix
Wolfram is pretty good at interpreting words
anonymous
  • anonymous
Does the mode matter?
zepdrix
  • zepdrix
The boundaries of your integral are radian measure. Hmm, so yes, maybe.
anonymous
  • anonymous
I'm getting a data type error. Is there a way to insert sin^2?
zepdrix
  • zepdrix
sin^2(sin(x)) is the same as (sin(sin(x)))^2 so maybe try that second way oh, I guess that's what you had in the first place though.
anonymous
  • anonymous
Yeah, I had that. Tells me wrong value or variable type.
zepdrix
  • zepdrix
Notice that Wolfram's exact solution involves the Bessel function of the first kind. So maybe your calculator can't handle fancy stuff like this one. I'm not sure :\
anonymous
  • anonymous
LOL I can't use wolfram when taking my exam doe, they proctor my online course exam at school, when my own teacher tells me I can cheat.
zepdrix
  • zepdrix
hmm true >.<
anonymous
  • anonymous
I'm just gonna use it and tell em my calculator is acting up so I'm using an online one.
anonymous
  • anonymous
Thanks man
zepdrix
  • zepdrix
ya np sorry we couldn't figure out the calculator :\ maybe ask teacher for assistance
anonymous
  • anonymous
Quick question if you don't mind.
anonymous
  • anonymous
and don't worry about it
anonymous
  • anonymous
I have a questions extremely similar to this one but has an equilateral triangle instead. Would I follow same steps but use the area formula of the triangle?
anonymous
  • anonymous
Oh wait, that one is cross sections.....it's different
zepdrix
  • zepdrix
maybe post the question? :) If I can look at it, it might refresh my memory
anonymous
  • anonymous
Ok, I'll tag you soon.

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