anonymous
  • anonymous
I'm confused
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
What does 0 to the power of 0 equal
anonymous
  • anonymous
0
anonymous
  • anonymous
0

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anonymous
  • anonymous
0
anonymous
  • anonymous
there is no NUMBER plus anything x by 0 is0 i deserve the medal i explained it
anonymous
  • anonymous
lol well played @DERRICKCURRY
anonymous
  • anonymous
I meant \[0^{0}\]
anonymous
  • anonymous
thx @Kawaii!!!2026
anonymous
  • anonymous
yea 0
anonymous
  • anonymous
@DERRICKCURRY I gave you my choice of best answer :P
anonymous
  • anonymous
Oh, ok
anonymous
  • anonymous
thx
anonymous
  • anonymous
0^{x} = 0^{1+x-1} = 0^{1} \times 0^{x-1} = 0 \times 0^{x-1}= 0 That's how u explain it :D
anonymous
  • anonymous
ok @Kawaii!!!2026 i got u
anonymous
  • anonymous
lol he acyually explained it better than meh
anonymous
  • anonymous
100%
anonymous
  • anonymous
man yea 100% dificult i did it the easy way to be honest
anonymous
  • anonymous
@DERRICKCURRY thx
anonymous
  • anonymous
np
anonymous
  • anonymous
jf the answer can be 1 or 0
rockstar0765
  • rockstar0765
HI
anonymous
  • anonymous
@Kawaii!!!2026 which one is it, though
anonymous
  • anonymous
It is commonly taught that any number to the zero power is 1, and zero to any power is 0. But if that is the case, what is zero to the zero power? Well, it is undefined (since xy as a function of 2 variables is not continuous at the origin). But if it could be defined, what "should" it be? 0 or 1?
anonymous
  • anonymous
I seriously don't know. My teacher says it's undefined, while other people say it's 1
tkhunny
  • tkhunny
Confused about what? \(0^{0}\) might result in "NaN", or something else that isn't a number. I believe you will find this to be the case in most programming languages. However, some give "1". You need to know what your language does or you will have programming anomalies. "Undefined" is a tough term. The word "Indeterminate" might be more appropriate in many situations. However, sometimes it is important to extend definitions for consistency. This might make \(0^{0} = 1\). Arguments involving limits are more difficult, since \((Actual\;0)^{(Actual\;0)}\) is not ever achieved. It's a LIMIT. There is no "AT". There is, however, a reliable value as you approach this situation. How often do you actually encounter \(0^{0}\)? It's not likely to be too often. I wouldn't worry about it too much.
anonymous
  • anonymous
@tkhunny thx

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