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An X value less than 0 is basically a negative number, right? So what you would do is go to the left side of the graph (Which is the negative side of the graph) and look for all points that lay on that side
So it is C. c, d, j ?
Awesome! Thank you so much :) Can you please help me with some more similar to this?
Sure, I don't mind
Yes, it is D. Good one!
For this one, remember you have to do the X value first and then the Y value (The run over rise method)
For the x value I see that it could be B.point B?
Point B is (2, -4), not (-2, 4). It's (2, 4) because the first value is x and the second is y. You went to the right two, which is positive instead of left two, which is negative. Same with the 4. When finding the Y value, being above 0 is positive (going up) and being below 0 in negative (going down) Hope that makes sense
It's C! (-2,4)
Yes! Did the X value first then the Y, good job!
This is the last one. @FortyTheRapper
Almost This one is quadrant placing. The first quadrant starts in the upper-right, as you got correct. But instead, you counted clockwise. You have to count counter-clockwise when counting quadrants
Yep, that's correct =]
Awesome! Than you so much. :)