anonymous
  • anonymous
A circle is centered at (3, 8) and is tangent to the x-axis. Write its equation in standard form.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Serenity74
  • Serenity74
My first question what is the equation of a circle?
anonymous
  • anonymous
it doesn't say this is all it gives me
Serenity74
  • Serenity74
Okay, you use (x-h)^2 +(y- k)^2 = r^2 given points (3,8)

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Serenity74
  • Serenity74
Wait is this Calculus?????
anonymous
  • anonymous
thanks and geometry
Serenity74
  • Serenity74
Oh gosh you scared me for a second lol and yea you just use that formula and do you know how to solve for the Radius??
anonymous
  • anonymous
they put me in the wrong class so i dont know what im doing and no
Serenity74
  • Serenity74
Lol I hate that! Happened to me with pre-calc but thankfully I got to stay in pre-calc. Did they not give you the radius? Cause usually they give you the radius in the question.
anonymous
  • anonymous
they placed me in acc geometry and i said cp geometry and then when they gave me my schedule they said they couldnt change me .-. and no like the question i wrote is the exact same thing of what they gave me
Serenity74
  • Serenity74
Hmmm let me review my notes real quick okay? I will get you the answer I swear or this will drive me nuts too lol.
anonymous
  • anonymous
ok lol thanks
Serenity74
  • Serenity74
I think after you plug in the coordinates into the equation you distribute it and then equal it to 0. After you are done with that let me know and show me the work you have done so far so i can see whether what you did was right or not.
anonymous
  • anonymous
so do you mean like foil it?
Serenity74
  • Serenity74
Yup!
anonymous
  • anonymous
so far i have x^2 - 6x + y^2 - 16y + 73 = 0
Serenity74
  • Serenity74
Yup, now do you know how to do completing the square method? I would explain it to you after you read the link i am about to send you. Just so you can get a glance off it of it mathematically and then my gibberish XD
anonymous
  • anonymous
yeah i know im doing it right now lol and thanks so much i really appreciate it
Serenity74
  • Serenity74
No problem! Let me know if you need anything us in the future! I will try my best in helping you :) Have a great day and peace.

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