anonymous
  • anonymous
How to find the acute angle that a constant unit force vector makes with the positive x-axis if the work done by the force in moving a particle from (0,0) to (4,0) equals 2.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
work = Fx x = displacement in force direction = √((0-0)^2 + (4-0)^2) = 4 units in the positive x direction 2 = F * 4 F = force = 2/4 = 1/2 N (the horizontal component of the force) F(horizontal) = F * cos Φ cosΦ = F(horizontal) / F = (1/2) / 1 = 1/2 Φ = arc cos 1/2 = 60 Source: https://answers.yahoo.com/question/index?=20130609074425AA336K6
IrishBoy123
  • IrishBoy123
or, for constant force, \(W = \vec F \bullet \vec x = |\vec F|| \vec x| \cos \theta = 2\) here \(|\vec F|\ = 1\) and \(|\vec x|\ = 4\)

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