cutiecomittee123
  • cutiecomittee123
Pre Calculus HELP!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Serenity74
  • Serenity74
Where is the question....lol
cutiecomittee123
  • cutiecomittee123
|dw:1449620459031:dw| In the triangle shown, what are the measurements of angles A, B, and C? Round your answers to the nearest 10th of a degree.
Serenity74
  • Serenity74
A, B, C are the angles!

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Serenity74
  • Serenity74
*angels
Serenity74
  • Serenity74
Lower case a, b, c are opposite from their Capital letter. a is opposite from A so the side for Angel A would be a = 6 b is opposite from B so the side for Angel B would be a =11 c is opposite from C so the side for Angel C would c = 7
Serenity74
  • Serenity74
Do you get it? Or do you need extra help? I don't mind giving you examples lol :) Good practice/ refreshing for me XD
cutiecomittee123
  • cutiecomittee123
Well I know that you need to set up three equations cos(a)=(b^2+c^2-a^2)/2bc (you do this for the b and c equations as well) then once you plug in the numbers, You have to take the inverse cos of the answer and then turn it into degrees.
Serenity74
  • Serenity74
Yes!!! Correct :)
Serenity74
  • Serenity74
Wait inverse cosine? That's based on...oh nvm! I getchu, lol took a while for me XD!
cutiecomittee123
  • cutiecomittee123
alright so for A, I got 29.79 because Cos(A)=(11^2+7^2-6^2)/2(11)(7) which is approximately 0.87 so cos^-1(0.87)=.52 radians then .52(180/pi)=29.79
Serenity74
  • Serenity74
I would like agree with you.
cutiecomittee123
  • cutiecomittee123
Okay and cos(b)=64.74 because cos(b)=(6^2+7^2-11^2)/(2(6)(7)) which is approximately 0.43 cos^-1(0.43)-1.13 1.13(180/pi)=64.74
cutiecomittee123
  • cutiecomittee123
@Serenity74 do you not remeber how to do this? I am kinda stuck because I got the answer for C, but when A, B, and, C add up they dont equal 180. and all triangles are 180 degrees so I am confused now.
johnweldon1993
  • johnweldon1993
Do you mind if I asked what you got for C? :)
johnweldon1993
  • johnweldon1993
I'll assume *since I see the mistake already* That you received 35.10 roughly for C correct?
johnweldon1993
  • johnweldon1993
Aww, must be away from the computer momentarily Regardless, your mistake lies with the calculation of B In the sense that \(\large cos(B) = \frac{6^2 + 7^2 - 11^2}{2(6)(7)}\) will DEFINITELY come out to a negative result :) *You just missed the negative sign..the result from that is -0.43 and the arccos of that is 115.37
cutiecomittee123
  • cutiecomittee123
I am back!
cutiecomittee123
  • cutiecomittee123
oh I see and now that we have B, 180-(A+C)=B
johnweldon1993
  • johnweldon1993
Well yeah exactly, you can use that to check :)
Serenity74
  • Serenity74
Sorrryyyy busy figuring out my physics project which I finally figured out and about to get egged and egg peeps lol. But yeah what @johnweldon1993 said is right. I got distracted sorry!!!
cutiecomittee123
  • cutiecomittee123
Okay well without using the check method, I went ahead and solved cos(c). Which was 34.95. It almost adds up but we have an point something so I think I may have calculated wrong
cutiecomittee123
  • cutiecomittee123
C should be 34.47
cutiecomittee123
  • cutiecomittee123
hmm I am a little lost in the calulculations because everytime I try to do cos(c) I am getting 34.95 but according to the check it should be 34.47
cutiecomittee123
  • cutiecomittee123
@johnweldon1993

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