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Can you help explain so I know how to it do in case I get another similar question like this?
the basic rule is just to get x by itself start with Equation 1: 3/4 (x − 12)=12 distribute the (3/4) (3/4)(x-12) = ?
uh not quite...
hint: A(B-C) = A*B - A*C (3/4)(x-12) = _________ follow the pattern
9? im not sure im having a hard time understanding these questions sorry if i'm making you overwhelmed or anything its not my intentions honestly.
meaning that A = 3/4, B = x, C = 12 now find A*B - A*C
so 3/4 * x and 3/4 *12
yes that gives us (3/4)x- 9 now we have (3/4)x - 9 = 12 now solve for x
(3/4)x - 9 = 12 add 9 to both sides
to 3/4 and 9?
no, you can't add 9 to (3/4) since (3/4) is attached to x
(3/4)x - 9 + 9 = ?
(3/4)x - 18 = 12
nope -9 + 9 = ?
good. so what is (3/4)x - 9 + 9 ?
(3/4)x = 12??
almost you also need to add 9 to the right side
(3/4)x - 9 = 12 becomes (3/4)x = 12 + 9 = 21 with me so far?
good (3/4)x = 21 now solve for x
good. so x = 28 ready for equation 2?
Thank you and yes
3/4 y − 12=12 again, we want to get y by itself start by adding 12 to both sides
3/4 y - 12 + 12
so um 3/4 y - 12 = 12
@Vocaloid am i right or am i speaking nonsense?
not quite (3/4)y - 12 + 12 = ??
sorry @Vocaloid connection is bad right now but i fixed it um (3/4)y - 12??
am i right? sorry for bothering you i just need help @Vocaloid
the - 12 and the 12 cancel out... (3/4)y - 12 + 12 = 12 + 12 (3/4)y = 24 solve for y
Thank you @Vocaloid for your patience and kindness (: take this medal as my appreciate
no problem, feel free to tag me anytime if I'm online