Abmon98
  • Abmon98
A bomber flying to the right with a horizontal velocity of 600m/s at an altitude of hkm is to score a direct hit on a train moving to the left with a constant velocity of 180m/s and at a horizontal distance 15km from the plane as shown. 1) Calculate the angle a between the line of sight the target and the horizontal at the instant the bomb should be released? 2)The velocity when it hits the train? 3)The time it takes the missile to hit the train 4) The direction of the missile when it hits the train.
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Abmon98
  • Abmon98
For part 1) Should we use the trajectory equation and set y=0 since the missile started at the projection level Sx=vtcosθ work out t given the horizontal distance 15km then use vx=vcosθ and vy=vsinθ−gt. Taking the square root of v2x+v2y to find the velocity of the missile when it hits the train. my main doubt about this question is that the train is moving, if the missile hits the train then it wont be at a horizontal distance 15km
anonymous
  • anonymous
Is the altitude of the plane given?
Abmon98
  • Abmon98
nope

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Abmon98
  • Abmon98
it's given as h thats it
IrishBoy123
  • IrishBoy123
first find t for when the bomb and rain are at the same position in the horizontal direction, ie \(600t + 180t = 15000\) as they will collectively have covered the 15km as the bomb ie being dropped, its equation of motion in the vertical direction will be \(y = (0)t + \frac{1}{2} g t^2\). you know g and t. you can therefore calculate the height, h, that it **has to be at** for the train and the bomb to collide.
Abmon98
  • Abmon98
@IrishBoy123 can we use relative velocity to be our initial speed of the bomb
IrishBoy123
  • IrishBoy123
sure you can.
Abmon98
  • Abmon98
Sorry to bother you again if you dont mind checking those answers 1) y=xtan(theta)-g/2(x/x0)^2 0=15*10^3tan(theta)-5(15*10^3/600)^2 theta=11.768 2) relative velocity=600-(-180)=780m/s Horizontal velocity=780cos11.768 vertical displacement=-3125 sy=-1/2gt^2 t=25 seconds vertical velocity=-g(25) sqaure root of vx^2+vy^2 3) 25 seconds 4) tanx=vy/vx
IrishBoy123
  • IrishBoy123
not sure if this helps....
1 Attachment
Abmon98
  • Abmon98
I Appreciate your help thank you

Looking for something else?

Not the answer you are looking for? Search for more explanations.