anonymous
  • anonymous
Please help with 4 questions ASAP medal+fan
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
anonymous
  • anonymous
2-5
anonymous
  • anonymous
@mathmate @mathmale

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anonymous
  • anonymous
anonymous
  • anonymous
Please help
anonymous
  • anonymous
@pooja195
anonymous
  • anonymous
@mathmate @mathwiz916 @mathmale @mathwizzard3 @MathematicalyExactOne
anonymous
  • anonymous
@mathmale
anonymous
  • anonymous
Can you please help
anonymous
  • anonymous
2-5 on this attachment
anonymous
  • anonymous
please help for fan and medal
anonymous
  • anonymous
someone help!
anonymous
  • anonymous
i am so confused i have been working for 3 hours and got 1 problem done
amy0799
  • amy0799
ok, I think I know how to do this. Can you tell me what the area of a circle is? and the circumference of a circle is?
anonymous
  • anonymous
a=pi times r
anonymous
  • anonymous
c=2pi times r
amy0799
  • amy0799
you forgot the squared for area. A=pi(r)^2
amy0799
  • amy0799
for the first problem, you want to set the given circumference to the equation, 2pi(r) 352=2pi(r)
anonymous
  • anonymous
oh yeah
anonymous
  • anonymous
i got 9859
anonymous
  • anonymous
but for 2-5 i didn't get
amy0799
  • amy0799
It's basically the same set up. For 2, 3 1/7 = pi(r)^2, solve for r, and plug it into the C=2pi(r)
anonymous
  • anonymous
what did you get
amy0799
  • amy0799
i got C=1.0272
anonymous
  • anonymous
Same
anonymous
  • anonymous
Let's do number 3
anonymous
  • anonymous
wait what did you get for number 1 i got 9859
anonymous
  • anonymous
is that what you got?
amy0799
  • amy0799
i got 9856
anonymous
  • anonymous
that's what i got the first time
amy0799
  • amy0799
that's due to rounding probably, i used 22/7 for pi
anonymous
  • anonymous
what did you get for number 3
amy0799
  • amy0799
did you already solve for it?
anonymous
  • anonymous
not yet i'm about to
amy0799
  • amy0799
i got my answer, tell me yours first
anonymous
  • anonymous
i don't get this one
anonymous
  • anonymous
i got something really off so i don't really want to say it
anonymous
  • anonymous
how do i solve this
amy0799
  • amy0799
the set up is exactly the same as question 2 15,400=2pi(r), solve for r and plug into C=2pi(r)
anonymous
  • anonymous
how do you solve for r
amy0799
  • amy0799
oops, that should be pi(r^2), because it's squared, you need to take the square root of it so \[\sqrt{15,400/22/7}\]
anonymous
  • anonymous
i don't get this
amy0799
  • amy0799
first solve for 15,400/2pi, what do you get? use 22/7 for pi
amy0799
  • amy0799
i keep messing up, sorry, 15,400/pi
anonymous
  • anonymous
i got this
amy0799
  • amy0799
that's because you divided it the other way around divide 15,400 by 22/7 15,400/(22/7)
anonymous
  • anonymous
100
amy0799
  • amy0799
plug what i have typed exactly, with the parenthesis
anonymous
  • anonymous
4900
amy0799
  • amy0799
good, now you need to square root it
anonymous
  • anonymous
24010000
amy0799
  • amy0799
that's squaring it square root is \[\sqrt{4900}\]
anonymous
  • anonymous
how do you square root it
amy0799
  • amy0799
do you have a calculator?
anonymous
  • anonymous
yes
amy0799
  • amy0799
is it Texas Instruments TI-30X?
anonymous
  • anonymous
yes
amy0799
  • amy0799
so hit the 2nd button on it, its in light blue, and then the square root symbol, which is under the ^ symbol
anonymous
  • anonymous
then what
amy0799
  • amy0799
plug in 4900 into the square root
amy0799
  • amy0799
did you get it?
anonymous
  • anonymous
1.001735585
amy0799
  • amy0799
for the square root of 4900?
anonymous
  • anonymous
yes
anonymous
  • anonymous
no 70
anonymous
  • anonymous
70
amy0799
  • amy0799
ok good, now plug in 70 into C=2pi(r) r is 70
anonymous
  • anonymous
i got 440
amy0799
  • amy0799
yay! correct
amy0799
  • amy0799
do you understand how to solve the rest now?
anonymous
  • anonymous
finally
anonymous
  • anonymous
not really
anonymous
  • anonymous
but i'll try
amy0799
  • amy0799
do you still need my help?
anonymous
  • anonymous
probably sorry
amy0799
  • amy0799
it's fine, can you try 4, you got the correct answer on this on 1, so it's the same setup
anonymous
  • anonymous
can you tell me the steps one more time
amy0799
  • amy0799
you are given the circumference, 12(4/7), 12(4/7)=2pi(r), solve for r and plug in the value of r into A=pi(r)^2
amy0799
  • amy0799
tell me what you get for r first
anonymous
  • anonymous
bro i know this sounds wrong but can you please give me the answers i have to go to bed
amy0799
  • amy0799
im sorry i cant do that, it's really not that hard
amy0799
  • amy0799
ill give you some help
amy0799
  • amy0799
|dw:1449629566837:dw|
anonymous
  • anonymous
bro i have to go i will give you a fan and a medal im sorry
amy0799
  • amy0799
|dw:1449629664052:dw|
amy0799
  • amy0799
last one is 13690
anonymous
  • anonymous
Thanks bye

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