anonymous
  • anonymous
Find all solutions to the equation. 7 sin^2x - 14 sin x + 2 = -5
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I have a basic understanding for these types of problems, I am just having some difficulty with this one.
Zarkon
  • Zarkon
\[7 u^2 - 14 u + 2 = -5\]
anonymous
  • anonymous
Yes just like that

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
For other problems I have factored, Im just not sure what to do with this one. Should I subtract -2 from both sides? Should I factor out the 7 from both sin terms?
Zarkon
  • Zarkon
\[7 u^2 - 14 u + 7=0\]
anonymous
  • anonymous
Okay thats what I did the first time. I then factored out 7 to be left with \[7(\sin^2x-2sinx+1)=0\]
Zarkon
  • Zarkon
\[7(\sin(x)-1)^2=0\]
anonymous
  • anonymous
That was the point where I ended. I didnt know where to take it from there.
Zarkon
  • Zarkon
\[\Large\Rightarrow \sin(x)-1=0\]
anonymous
  • anonymous
Which we would need to isolate the sin to get \[sinx=1\]
anonymous
  • anonymous
What happens to the 7 though?
Zarkon
  • Zarkon
divide both sides by 7
anonymous
  • anonymous
so sinx=1/7? The only thing that confuses me about that, is that there is no sine or y value on the unit circle that is 1/7
Zarkon
  • Zarkon
no
Zarkon
  • Zarkon
\[7(\sin(x)-1)^2=0\] \[\Rightarrow (\sin(x)-1)^2=0/7=0\]
Zarkon
  • Zarkon
so you need just to find \[\sin(x)=1\]
anonymous
  • anonymous
how does 0/7=0?
anonymous
  • anonymous
ohhhhh
anonymous
  • anonymous
Nevermind I get it now
Zarkon
  • Zarkon
zero divided by any nonzero number is zero
anonymous
  • anonymous
Thank you so much!
anonymous
  • anonymous
That would be like multiplication. 0 times any number is zero.

Looking for something else?

Not the answer you are looking for? Search for more explanations.