can anyone please tell me "what conditions must be met in order for a sampling distribution of proportions to be approximated by a normal distribution" I cant seem to understand when I look it up.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
I do appreciate your having looked this up. Would you mind typing out the two conditions you've found? I don't have a reference in front of me at the moment, other than the Internet, but recall that Sqrt(np(1-p) ) is part of one of the conditions.
n is the number of samples. What does p represent?
Not the answer you are looking for? Search for more explanations.
Have you found an inequality that looks like Sqrt(np(1-p) )? One of the conditions for assuming a normal distribution is that this quantity is greater than or equal to 10. Can you confirm or correct this? Again, i don't have a reference book here with me, so am relying on memory for something I haven't used in 2 years.
While OpenStudy was down, I did a little research and found what I'd thought we needed to decide whether or not we could assume a normal distribution:
Please have a look at :
Just above "Recommends," you'll see that the requirements are \[np \ge 10, and . n(1-p) \ge 10\]
Hope this is helpful. Unfortunately, I need to get off the 'Net now. Sorry.
Thanks you and yes you were right! I checked it and its like you said. Again thank you :)