anonymous
  • anonymous
Haziq drops a ball from a height of H cm above the floor.After the 1st bounce,the ball reaches a height of h_1 cm where H_1=2(H)/3.After the 2nd bounce,the ball reaches a height of H_2 cm where H_2=2(H_1)/3.The ball continue bouncing in this way until it stops. Given that H=600cm,find a) the number of bounces when the maximum height of the ball from the floor is less than 100 cm for the first time. @tkhunny
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
This is my working...maybe u could check my working whether is it correct or not\[a=\frac{ 2 }{ 3 }(600)=400cm~and~r=\frac{ 2 }{ 3 }\]\[T_n<100\]\[400(\frac{ 2 }{ 3 })^{n-1}<100\]\[(\frac{ 2 }{ 3 })^{n-1}<\frac{ 1 }{ 4 }\]\[(n-1)\log_{10}\frac{ 2 }{ 3 }<\log_{10}\frac{ 1 }{ 4 }\]\[n-1<3.419\]\[n<4.419\]\[n=4\]
anonymous
  • anonymous
@tkhunny
tkhunny
  • tkhunny
600(2/3) = 400 - 1st Bounce 400(2/3) = 266 2/3 - 2nd Bounce 266 2/3(2/3) = 177 7/9 - 3rd Bounce 177 7/9(2/3) = 118.518518... - 4th Bounce 118.518518...(2/3) = 79ish - 5th Bounce Where did you wander off?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so this mean n=5
anonymous
  • anonymous
Thank you @tkhunny
tkhunny
  • tkhunny
You did not yet find your error. It's there. Look harder.
anonymous
  • anonymous
Can u show me what error i did in my working pls? is it the symbol?
tkhunny
  • tkhunny
This is the first incorrect step: \(n - 1\;<\;3.419\)
anonymous
  • anonymous
Thank you @tkhunny :) :D
tkhunny
  • tkhunny
What happened? Did you see it? It's sneaky. :-)
anonymous
  • anonymous
yes i see it...
anonymous
  • anonymous
n-1>3.419
anonymous
  • anonymous
bcoz the log is negative multiply with n
tkhunny
  • tkhunny
It didn't LOOK negative when it was written as a logarithm, did it? Good work.
anonymous
  • anonymous
yes
anonymous
  • anonymous
Thank you @tkhunny :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.