anonymous
  • anonymous
FAN AND MEDAL https://i.gyazo.com/331c41eddf5d2650d41f61dc80d4e548.png ??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
kimberlyevens
  • kimberlyevens
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
|dw:1449639459391:dw|
jim_thompson5910
  • jim_thompson5910
let's add the variables x and y |dw:1449639599147:dw|

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jim_thompson5910
  • jim_thompson5910
are you able to find the value of x?
jim_thompson5910
  • jim_thompson5910
hint: pythagorean theorem
anonymous
  • anonymous
I believe the answer is 2cm
jim_thompson5910
  • jim_thompson5910
how did you get to that answer
jim_thompson5910
  • jim_thompson5910
can you tell me what you got for x and y?
anonymous
  • anonymous
Since the first triangle's base is 1, then x and y would be 1
jim_thompson5910
  • jim_thompson5910
x is not 1
jim_thompson5910
  • jim_thompson5910
|dw:1449639980162:dw|
anonymous
  • anonymous
I believe 2
jim_thompson5910
  • jim_thompson5910
a^2 + b^2 = c^2 1^2 + 1^2 = x^2 x = ???
anonymous
  • anonymous
2^2 which would be 4, right? I'm sorry I'm slow at this
jim_thompson5910
  • jim_thompson5910
1^2+1^2 = 2 so \[\Large x^2 = 2\] which means \[\Large x = \sqrt{2}\]
jim_thompson5910
  • jim_thompson5910
|dw:1449640161367:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1449640177582:dw|
anonymous
  • anonymous
So we repeat this process until we get to h?
jim_thompson5910
  • jim_thompson5910
yes
jim_thompson5910
  • jim_thompson5910
now we have this triangle |dw:1449640238899:dw|
anonymous
  • anonymous
that would be 1^2 + 2^2 , right?
anonymous
  • anonymous
1^2+2^2= y?
jim_thompson5910
  • jim_thompson5910
\[\Large a^2 + b^2 = c^2\] \[\Large 1^2 + (\sqrt{2})^2 = y^2\] \[\Large 1 + 2 = y^2\] y = ???
anonymous
  • anonymous
3^2 and then we do the same we did with the first triangle and that gives us \[\sqrt{3}\] ?
anonymous
  • anonymous
so y would be \[\sqrt{3}\]
jim_thompson5910
  • jim_thompson5910
yep, y = sqrt(3) |dw:1449640445671:dw|
anonymous
  • anonymous
So this last part would be 1+3= y^2 which leads to 4 square rooted? and thats h, right?
jim_thompson5910
  • jim_thompson5910
yep, so h is definitely 2 btw if you keep up the pattern, you get what you see here https://en.wikipedia.org/wiki/Spiral_of_Theodorus
anonymous
  • anonymous
Thank you !! I really appreciate this and you're great at math
jim_thompson5910
  • jim_thompson5910
you're welcome

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