anonymous
  • anonymous
Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle between the sides a and b of ∆ABC is more than 90°?
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
area of square c2 = -area of square a2 – area of square b2 + area of defect1 + area of defect2 area of square c2 = area of square a2 + area of square b2 + area of defect1 – area of defect2 area of square c2 = area of square a2 + area of square b2 – area of defect1 – area of defect2 area of square c2 = area of square a2 + area of square b2 + area of defect1+ area of defect2 area of square c2 = area of square a2 - area of square b2 + area of defect1 - area of defect2
tygrr321
  • tygrr321
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anonymous
  • anonymous
wich do you think it is?

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anonymous
  • anonymous
Honestly, I have no clue what their even asking.
anonymous
  • anonymous
hmm
anonymous
  • anonymous
I basically need step by step help on Geometry because I literally cant comprehend what to do.
anonymous
  • anonymous
I am not sure about the "defects method", perhaps if you could post the original term (assuming it is in a different language than English) it would be a little easier. However, to find out if the included angle of a triangle is greater than 90 degrees, we need to use the cosine rule if the measures of the three sides are known. With the usual conventions of cosine rule, where angle A is opposite side of length a, etc, we calculate cosA=b2+c2−a22bc If cos A is negative, angle A is greater than 90 degrees. This test is useful when working with the sine rule, which gives ambiguous results under certain circumstances (e.g. when only one angle is known or given)
anonymous
  • anonymous
|dw:1449640539952:dw|
anonymous
  • anonymous
@LilliBelle
anonymous
  • anonymous
There you go.:D
anonymous
  • anonymous
Okay so I'm thinking it would be A then
anonymous
  • anonymous
I cant tell you the answer:P

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