safyousuff97
  • safyousuff97
Given the function f(x) = 2(3)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average rate of change of each section. (4 points) Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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safyousuff97
  • safyousuff97
@rvc
rvc
  • rvc
@mathmate
mathmate
  • mathmate
I suspect the function is meant to be \(2(3^x)\) in which case the rates of change would be different between the two sections.

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More answers

safyousuff97
  • safyousuff97
yes except 2(3) x on the top
mathmate
  • mathmate
average rate of change is given by \(\Delta y/\Delta x\), so for the first section, average rate of change =\((f(1)-f(0))/(1-0)=(2*3^1-2*3^0)/(1-0)=4\) You can calculate the average rate of change for the other interval similarly
safyousuff97
  • safyousuff97
i'm sorry i'm confused can u explain what u just did?
safyousuff97
  • safyousuff97
@mathmate
caozeyuan
  • caozeyuan
top is f(end)-f(start), bottom is end-start
Nnesha
  • Nnesha
what a coincidence.. what grade are u in??
safyousuff97
  • safyousuff97
9th
Nnesha
  • Nnesha
cool.
Nnesha
  • Nnesha
for section A first you need to find y (or find f(1) ,f(0)values when x=1 ,x=0 substitute x for 1 and 0 solve for y \[\rm f(1)=2(3)^1 \] what would you get when u substitute x for 1 ??? f(1)= ?

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