princesssleelee
  • princesssleelee
Which function below is the inverse of f(x) = x2 − 36? x squared over 36 ±6square root of x 1 over quantity x squared minus 36 ±square root of the quantity x plus 36
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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MD152727
  • MD152727
f(x) = x^2 - 36 y = x^2 - 36 .... replace f(x) with y x = y^2 - 36 .... swap x and y now solve for y to get the inverse
princesssleelee
  • princesssleelee
solve for y=x^2 -36, correct?
MD152727
  • MD152727
yes

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princesssleelee
  • princesssleelee
Being option D?
princesssleelee
  • princesssleelee
\[\pm \sqrt{x+36}\]
MD152727
  • MD152727
Nope
MD152727
  • MD152727
f(x) = x^2 - 36 y = x^2 - 36 .... replace f(x) with y x = y^2 - 36 .... swap x and y now solve for y to get the inverse
MD152727
  • MD152727
f(x)=y=x2−36inverse⟹x=y2−36 notice to get the "inverse relation", we'd firsts swap about the variables, then solve for "y"
princesssleelee
  • princesssleelee
I tried that, I cant get it.
MD152727
  • MD152727
f(x)=y=x2−36inverse⟹x=y2−36x+36=y2then take −−−−√ to both sides
MD152727
  • MD152727
consider f(x) = y y = x^2 - 36 y+36 = x^2 x = sqrt(y+36) now consider f(x) = y => x =f^-1(y) => f^-1(y) = sqrt(y+36) therefore f^-1(x) = sqrt(x+36) Did you get it now???
MD152727
  • MD152727
? :?
Pawanyadav
  • Pawanyadav
Yes,, D is right
princesssleelee
  • princesssleelee
I'm sorry, no. I get a complete mind block.
princesssleelee
  • princesssleelee
@Pawanyadav How did you conclude "D"
Pawanyadav
  • Pawanyadav
As you already have y+36=x^2 So for inverse interchange x,y You will get x+36=y^2 Square root both side +-√(x+36)=y so D
princesssleelee
  • princesssleelee
Okay, thank you.
Pawanyadav
  • Pawanyadav
You're welcome

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