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Start by drawing a figure. Draw a rectangle that is wider than high. Draw a diagonal.
Great. Now we look at it as if the length really were 16 in. and the height 9 in. Let's label it. |dw:1449683787154:dw|
If the TV had width 16 in. and height 9 in., what would the diagonal be?
Are you familiar with the Pythagorean theorem?
Correct. What is that equal to?
Great. Let's add that to our figure too. |dw:1449684141919:dw|
Ok. A TV 16 in. by 9 in. has a diagonal 18.37 in. Now you can do a proportion. If a diagonal of 18.36 in. has a height of 9 in., a diagonal of 50 in. has a height of x. Use a proportion to find x.
50 is x
Did I solve this properly ? is 50 x?
umm..sorry dude..i'm not sure :/
No, you didn't finish solving.
What is 450/18.36 ?
Why did you remove the problem? It is good to keep the problem because the solution may be helpful to other people.
Didn't the problem state to find the answer to the nearest tenth? Of course, I can't see it any more, so I'm not sure. If so, then it should be 24.5 in., not 24.50 in.