Chrisg094
  • Chrisg094
i need help with math
Algebra
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
what you need?
anonymous
  • anonymous
what do you need
Chrisg094
  • Chrisg094
|dw:1449687582469:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Chrisg094
  • Chrisg094
and also
misty1212
  • misty1212
HI!!
Chrisg094
  • Chrisg094
|dw:1449687727209:dw|
misty1212
  • misty1212
divide each term by \(7x^5\)
Chrisg094
  • Chrisg094
hello
misty1212
  • misty1212
for example \[\frac{21x^8}{7x^5}=3x^3\]
Chrisg094
  • Chrisg094
Can that be done, because they have the same base terms but the x values are different
misty1212
  • misty1212
\[-\frac{35x^7}{7x^5}=-5x^2\]and so on
misty1212
  • misty1212
divide term by term you can always divide divide the coefficients, subtract the exponents
Chrisg094
  • Chrisg094
just give me a sec and tell me if I get it right, please
misty1212
  • misty1212
\[\frac{\sqrt7+\sqrt2}{\sqrt7-\sqrt2}=\frac{\sqrt7- +\sqrt2}{\sqrt7-\sqrt2}\times\frac{\sqrt7+\sqrt2}{\sqrt7+\sqrt2}\]
misty1212
  • misty1212
the denominator will be \[7-2=5\] and the numerator will be whatever you get when you multiplyi \[(\sqrt7+\sqrt2)(\sqrt7+\sqrt2)\]
Chrisg094
  • Chrisg094
|dw:1449688082422:dw|
Chrisg094
  • Chrisg094
misty1212, that part confuses me. Your multiplying by the square root of 7 + the square root of 2, top and bottom why does the bottom stay the same in confused
Chrisg094
  • Chrisg094
I ended up with \[9\sqrt{4}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.