Maddy1251
  • Maddy1251
Sort of physics/math question. Not sure really what to do? If someone would give me some tips/guidance, I'd appreciate it. A 15.0kg block of mass is placed on a flat surface and pulled so that it eventually begins to move. Attached is a graph of the friction acting on this object while it is being pulled. Explain what this graph means and provide values for the force necessary to get the object moving and the force required to keep the block moving at a constant speed.
Mathematics
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SOLVED
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chestercat
  • chestercat
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Maddy1251
  • Maddy1251
1 Attachment
Maddy1251
  • Maddy1251
I'm really not sure what the 'x' axis is, that also is confusing me, too. :P
anonymous
  • anonymous
this is hard

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Maddy1251
  • Maddy1251
@sameri I know, I am trying to figure it out right now. I've been doing this stuff since 10AM and I am like wanting to be done.. :P
Maddy1251
  • Maddy1251
@IrishBoy123 @dan815 @ganeshie8 any ideas? is it static friciton?
IrishBoy123
  • IrishBoy123
try it for yourself. push a book on a flat surface and once you get it moving the resistance seems to drop. static and dynamic friction are different and different coefficients of friction. hence that blip thing in yr chart
Maddy1251
  • Maddy1251
@IrishBoy123 So, I am gonna go out on a limb and say it's dynamic and static. Because Static friction is the friction that exists between a stationary object and the surface on which it's resting. A frictional force occurs when you try to push an object alongside a surface. Once the objects have already started moving, kinetic friction takes, but then dynamic comes into place, the force that must be overcome to maintain steady motion of one body relative to another because they remain in contact. So, is this were the little flaw comes frm?
sweetburger
  • sweetburger
Yea I believe the coefficient of static friction is most definitely higher therefore you would have to exert a greater amount of force to exceed that threshold and the coefficient of kinetic friction is usually significantly lower so the force required to keep the object moving is not as high.
Maddy1251
  • Maddy1251
@sweetburger Gotcha. Thanks for that, that really helps.
sweetburger
  • sweetburger
glad to help :)
IrishBoy123
  • IrishBoy123
+1 @sweetburger

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