Chrisg094
  • Chrisg094
I need help with algebra
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Chrisg094
  • Chrisg094
\[\frac{ 1 }{ y+5} - \frac{ 5 }{ y-5 } = \frac{ 14 }{ y^2-25}\]
bemoseemo
  • bemoseemo
solve for y?
Chrisg094
  • Chrisg094
\[f(x)=\sqrt{12-4x}\]

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Chrisg094
  • Chrisg094
the first one says Solve the rational equation
bemoseemo
  • bemoseemo
second one is slightly easier xD but ok lets start and ill help ya work it through
Chrisg094
  • Chrisg094
then the last question i posted says, find the domain of the square root function and write it in interval notation
Chrisg094
  • Chrisg094
Okay thanks.
bemoseemo
  • bemoseemo
In mathematics, an interval is a set of real numbers with the property that any number that lies between two numbers in the set is also included in the set. For example, the set of all numbers x satisfying 0 ≤ x ≤ 1 is an interval which contains 0 and 1, as well as all numbers between them.
whpalmer4
  • whpalmer4
\[\frac{ 1 }{ y+5} - \frac{ 5 }{ y-5 } = \frac{ 14 }{ y^2-25}\]Can you factor the denominator on the fraction on the right hand side? I think once you do that, it will be easier to proceed. I would multiply both sides of the equation by \((y+5)(y-5)\) to clear the fractions. From there you should have no problem, I hope, but give a shout (and show your work) if you do...
Chrisg094
  • Chrisg094
I don't know how you would multiply that into the equation.
Chrisg094
  • Chrisg094
|dw:1449723025765:dw|
whpalmer4
  • whpalmer4
\[\frac{ 1 }{ y+5} - \frac{ 5 }{ y-5 } = \frac{ 14 }{ y^2-25}\] Let's factor that right hand side denominator: \[y^2-25 = (y+5)(y-5)\](because it is a difference of squares) \[\frac{ 1 }{ y+5} - \frac{ 5 }{ y-5 } = \frac{ 14 }{ (y+5)(y-5)}\] Now let's clear fractions by multiplying by all of the factors of all of the denominators: \[(y+5)(y-5)*\frac{1}{(y+5)} - (y+5)(y-5)\frac{5}{(y-5)} = (y+5)(y-5)\frac{14}{(y+5)(y-5)}\]when the dust settles on that, you have \[(y-5)*1 -(y+5)*5 = 14\] That should be straightforward to solve, right?

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