haleyelizabeth2017
  • haleyelizabeth2017
What is the standard form of the equation with rho=18, phi=(5pi)/4? Please no direct answers I have gotten to: x cos phi + y sin phi - p=0 x cos (5 pi/4) + y sin (5 pi/4) - 18 = 0 But I have no idea on where to go from here.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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shaleiah
  • shaleiah
@Nnesha
shaleiah
  • shaleiah
@Directrix
xapproachesinfinity
  • xapproachesinfinity
you rectangular form?

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xapproachesinfinity
  • xapproachesinfinity
the very fact that you talking about rho=18 i think you were essentially looking for a rectangular equation
xapproachesinfinity
  • xapproachesinfinity
converting from spherical to rectangular x^2+y2+z^2=rph^2
xapproachesinfinity
  • xapproachesinfinity
rho^2
xapproachesinfinity
  • xapproachesinfinity
hey talk to me! haha so i know what exactly you want to find
haleyelizabeth2017
  • haleyelizabeth2017
Sorry haha was afk
xapproachesinfinity
  • xapproachesinfinity
i see this is not conversion anyway
haleyelizabeth2017
  • haleyelizabeth2017
I have no idea...the information ^^ up there was all I was given.
xapproachesinfinity
  • xapproachesinfinity
so the standard form is given by xcos(phi)+ysin(phi)-p=0
xapproachesinfinity
  • xapproachesinfinity
which you already did xcos(5pi/4)+ysin(5pi/4)-18=0
haleyelizabeth2017
  • haleyelizabeth2017
yeah...
xapproachesinfinity
  • xapproachesinfinity
now you just need to evaluate cos(5pi/4) and sin(5pi/4)
xapproachesinfinity
  • xapproachesinfinity
you should be familiar with trigonometry, so what the problem here?
haleyelizabeth2017
  • haleyelizabeth2017
One second..
xapproachesinfinity
  • xapproachesinfinity
cos(5pi/4)=?
haleyelizabeth2017
  • haleyelizabeth2017
.998
haleyelizabeth2017
  • haleyelizabeth2017
sin(5pi/4)=.068
xapproachesinfinity
  • xapproachesinfinity
don't use calculator! if you know trig you know that \[\cos (\pi/4) =\sqrt{2}/2\]
haleyelizabeth2017
  • haleyelizabeth2017
-_-
xapproachesinfinity
  • xapproachesinfinity
but we are looking for 5pi/4 so you need to know what quadrant is the angle 5pi/4 in
xapproachesinfinity
  • xapproachesinfinity
|dw:1449699402571:dw|
xapproachesinfinity
  • xapproachesinfinity
that angle is in the 3th quadrant so cos there is negative then cos(5pi/4)=-sqrt(2)/2
xapproachesinfinity
  • xapproachesinfinity
with the same strategy sin(5pi/4)=-sqrt(2)/2 so the equation becomes \[-\frac{\sqrt{2}}{2 }x-\frac{\sqrt{2}}{2}y=18\]
haleyelizabeth2017
  • haleyelizabeth2017
Sorry

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