princesssleelee
  • princesssleelee
Which function below is the inverse of f(x) = The quantity of four x minus three, over two.? f−1(x) = two over the quantity of four x minus three f−1(x) = two over the quantity of three minus four x f−1(x) = The quantity of two x minus three, over four f−1(x) = The quantity of two x plus three, over four
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
b
anonymous
  • anonymous
\[f(x)=\frac{4x-3}{2}\]?
anonymous
  • anonymous
if so, it is definitely not B

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princesssleelee
  • princesssleelee
@satellite73 yes
anonymous
  • anonymous
ok it is the same as solving say \[\frac{4x-3}{2}=7\]
anonymous
  • anonymous
you know how to solve that?
princesssleelee
  • princesssleelee
no lol
anonymous
  • anonymous
oh then you are not going to like this !
princesssleelee
  • princesssleelee
darn it
anonymous
  • anonymous
\[\frac{4x-3}{2}=7\] multply by 2 get \[4x-3=14\]
princesssleelee
  • princesssleelee
ok
anonymous
  • anonymous
add \(3\) and get \[4x=17\] then divide by 4 to finish with \[x=\frac{17}{4}\]
anonymous
  • anonymous
now we are going to do the same thing with variables you havef \[f(x)=\frac{4x-3}{2}\] lets write it as \[y=\frac{4x-3}{2}\]
anonymous
  • anonymous
then switch x and y (because that is what the inverse does) and get \[x=\frac{4y-3}{2}\] solve for \(y\) the steps are the same as above
anonymous
  • anonymous
\[\frac{4y-3}{2}=x\] multiply by 2 get \[4y-3=2x\]
anonymous
  • anonymous
add 3 get \[4y=2x+3\] then divide by 4 to get \[y=\frac{2x+3}{4}\]
princesssleelee
  • princesssleelee
very very confusing but ill try
anonymous
  • anonymous
and that is your inverse \[f^{-1}(x)=\frac{2x+3}{4}\]
anonymous
  • anonymous
it is confusing if you cannot solve \[\frac{4x-3}{2}=7\] but the steps are only three : multiply by 2 add 3 divide by 4
anonymous
  • anonymous
that is what the inverse function \[f^{-1}(x)=\frac{2x+3}{4}\] does
princesssleelee
  • princesssleelee
x=−32+2y
princesssleelee
  • princesssleelee
i have no clue lol
anonymous
  • anonymous
you lost me there i wrote the steps above, see if you can follow them if not let me know all is written out i did not skip any
princesssleelee
  • princesssleelee
x=4.25
princesssleelee
  • princesssleelee
@satellite73
anonymous
  • anonymous
yes that is with the numbers now take a look at the same steps with i wrote it with variables
princesssleelee
  • princesssleelee
i dont know what to do there
anonymous
  • anonymous
i did it for you follow the steps to the answer
princesssleelee
  • princesssleelee
do i plug in the x
anonymous
  • anonymous
follow the post starting with "now we are going to do the same thing with variables"
princesssleelee
  • princesssleelee
i have no idea what I do with the steps?
anonymous
  • anonymous
follow them i did it for you
princesssleelee
  • princesssleelee
i cant figure it out to save my life

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