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Use Pythagoras relationship. A^2 + b^2= c^2
c would be the hypotenuse so c^2 = a^2 + b^2 19^2 = 3^2 + b^2 361 = 9 + b^2 352 = b^2 b = sq root (352)
Ok I found the side c=18.8 but I need to find Angels now
yes side c = 18.7616630393 To find the angles you need to use trigonometry
It would help to have a graphic - I'll make one
I have no idea what to use please help me to solve this
In triangle ABC, triangle C is a right angle. Find the remaining sides and angles. Round your answer to the nearest tenth. a=3, c=19 sin(A) = 3/19 ------------ B = 90 - A
ur anwers above
What is B== 90-A is ? I lost
sin(A) = 3/19 ------------ B = 90 - A
did it at least help you my explanation
the sine of angle a = opposite/hypotenuse the sine of angle a = 3/19
we need to find what angle has a sine of 0.1578947368 (which is 3/19) To do this we need to find the arc sine of 0.1578947368 Here's a good calculator to use: http://www.1728.org/trigcalc.htm
Please help me find that please
Okay if you go to the calculator, input 0.1578947368 where it says Input >>> <<<
After that what to solve?
You are solving for angle a which equals 9.0847 Degrees Then to solve angle b you calculate 90 - 9.0847 Degrees which equals 80.9153 degrees
That should be all the sides and angles you had to solve. Any questions about any of that?
What is arcsine means? Is inverse of sine?
I'm have only It84
Is asine is inverse of sine?
I'm still confused on sinA =c/b ................................................ B=90-A. What it means ? Please