anonymous
  • anonymous
Where is the vertex of the graph of f(x)= |x+2|+4? I will give medals
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Nnesha
  • Nnesha
`f(x−h)` here h is horizontal shift `f(x) + k` here k is vertical shift y=a(x-h)^2+k whihc is same as y=aIx-hI+k if h is negative graph will shift h unit to the right if h is positive graph will shift h unit to the left if k is positive graph shift k unit upp if k is negative some unit down
anonymous
  • anonymous
Uh what?
Nnesha
  • Nnesha
oh vertex. vertex form equation where \[\rm y=a \left| x-h \right|+k\] (h,k) is the vertex

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anonymous
  • anonymous
So what's the vertex for my problem?
whpalmer4
  • whpalmer4
Your equation: \[f(x)= |x+2|+4\] general vertex form equation: \[f(x) = a|x-h|+k\]compare the two and figure out the values of \(a,h,k\) you need to make them identical. Your vertex will be at \((h,k)\)
anonymous
  • anonymous
So my answer is (2,4)?
Nnesha
  • Nnesha
there is a negative sign in the original equation \[\rm y=a \left| x \color{ReD}{-h} \right|+k\] now compare ur equation \[\rm y=a \left| x \color{ReD}{+2} \right|+4\] which is same as as \[\rm y=a \left| x -\color{ReD}{(-2)} \right|+4\] - times - = positive 2 or in other words if there is `+h` then x-coordinate of the vertex would be negative and if it's `-h` then x-coordinate would be positive |dw:1449763281995:dw|
whpalmer4
  • whpalmer4
There is a great deal of educational value in checking your work! Got an answer for this problem? Make a graph from the equation and see if you get the vertex in the same place. It may seem like mindless tedium, but actually going through the motions of doing the work, rather than simply reading someone else's work and saying "uh huh" will result in much better understanding and proficiency.

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