Ranya99
  • Ranya99
. Trained shepherding dogs take the following path to gather the sheep in the field and bring them in for sheering. Let’s consider the lead dog’s motion. First he runs to the edge of the pasture (120, -200)m the he starts working the sheep. 90m at an angle of 160º, then 50m at an angle of 170º, then finally 165m at an angle of 60º. What is the dogs distance of running and what is the displacement?
Physics
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SOLVED
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jamiebookeater
  • jamiebookeater
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Ranya99
  • Ranya99
@IrishBoy123 can I send the drawing on your email, because its not posting here
IrishBoy123
  • IrishBoy123
screen grab it using gyazo then post a link its much easier
Ranya99
  • Ranya99
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IrishBoy123
  • IrishBoy123
try this for size displacement in x will be \(120 + 90 \cos (160) + 50 \cos(170) + 165 \cos(60)\) in y, \(-200 + 90 \sin (160) + 50 \sin(170) + 165 \sin(60)\)
Ranya99
  • Ranya99
Displacement Convert all to rectangular (120, -200) (120,-200) (90m, 160*) 90(sin70* more than north 90*) = 84.6 left 90(cos70*) = 30.8 up (-84.6,30.8) (50m, 170*) 50(sin80* more than north 90*) = 49.2 left 50(cos80* ) = 8.7 up (-49.2,8.7) (165, 60*) 165(sin60*) = 142.9 up 165(cos60*) = 82.5 right (82.5,142.9) Add them up……. (68.7, -17.6) The question asks for the displacement of running – that would be the hypoteneuse of these rectangular coordinates…….sqrt(68.7^2 + 17.6^2) = 70.9m Also asked for distance and that would be all the lengths added up 233.23 (the hyp of (120,-200) 90 50 165 Total distance = 538.23
Ranya99
  • Ranya99
Is this right?
IrishBoy123
  • IrishBoy123
looks good. displacement numbers agree haven't checked the actual distance number but that is the easy one and method looks good
Ranya99
  • Ranya99
alright thanks

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